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A lot of 20 semiconductor chips contains 5 that are defective. Two are selected randomly, without replacement, from the lot. What is the probability that the second one selected is defective given that the first one was defective? 4/20 4/19 O 1/19 D Question 3 is Suppose A and B are mutually exclusive events. What is P(A|B)? 1/2

A lot of 20 semiconductor chips contains 5 that are defective. Two are selected randomly, without replacement, from the lot. What is the probability that the second one selected is defective given that the first one was defective? 4/20 4/19 O 1/19 D Question 3 is Suppose A and B are mutually exclusive events. What is P(A|B)? 1/2

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A lot of 20 semiconductor chips contains 5 that are defective. Two are selected randomly, without replacement, from the lot. What is the probability that the second one selected is defective given that the first one was defective? 4/20 4/19 О 1/19 D Question 3 is Suppose A and B are mutually exclusive events. What is P(A|B)? O 1/2
Transcribed Image Text:A lot of 20 semiconductor chips contains 5 that are defective. Two are selected randomly, without replacement, from the lot. What is the probability that the second one selected is defective given that the first one was defective? 4/20 4/19 О 1/19 D Question 3 is Suppose A and B are mutually exclusive events. What is P(A|B)? O 1/2
Samples of a cast aluminum part are classified on the basis of surface finish and length measurements. The results of 100 parts are summarized as follows: Excellent Good Length Length Excellent 80 2 Finish Good Finish 10 We define 2 events: A: A selected part has excellent finish B: A selected part has excellent length What are P(A|B) and P(B|A)? O P(A|B)=80/82, P(B|A)=80/9O O P(A|B)=80/100, P(B|A)=1 O P(A|B)=80/90, P(B|A)=80/82
Transcribed Image Text:Samples of a cast aluminum part are classified on the basis of surface finish and length measurements. The results of 100 parts are summarized as follows: Excellent Good Length Length Excellent 80 2 Finish Good Finish 10 We define 2 events: A: A selected part has excellent finish B: A selected part has excellent length What are P(A|B) and P(B|A)? O P(A|B)=80/82, P(B|A)=80/9O O P(A|B)=80/100, P(B|A)=1 O P(A|B)=80/90, P(B|A)=80/82
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