A long, straight wire perpendicular to this page carries a current of 4.61 A directed into the page. Find the magnetic field at the following points, all 10.2 cm from the wire. (a) 10.2 cm to the left of the wire magnitude direction ---Select-- C (b) 10.2 cm directly below the wire magnitude direction ---Select-- C (c) 10.2 cm to the right of the wire magnitude direction --Select-- C (d) 10.2 cm directly above the wire magnitude direction ---Select--- C

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### Magnetic Field Due to a Current-Carrying Wire

A long, straight wire perpendicular to this page carries a current of **4.61 A** directed into the page. Find the magnetic field at the following points, all **10.2 cm** from the wire.

#### (a) 10.2 cm to the left of the wire
- **Magnitude:** [Text Box]
- **Direction:** [Dropdown Menu]

#### (b) 10.2 cm directly below the wire
- **Magnitude:** [Text Box]
- **Direction:** [Dropdown Menu]

#### (c) 10.2 cm to the right of the wire
- **Magnitude:** [Text Box]
- **Direction:** [Dropdown Menu]

#### (d) 10.2 cm directly above the wire
- **Magnitude:** [Text Box]
- **Direction:** [Dropdown Menu]

### Explanation of Magnetic Field Direction
The magnetic field around a current-carrying wire follows the right-hand rule. When the thumb of the right hand points in the direction of the current, the fingers curled around the wire point in the direction of the magnetic field: 

- **Into the page:** Use the right-hand rule.
    - Points to the left of the wire: Magnetic field points into/out of the page.
    - Points below the wire: Magnetic field points into/out of the page.
    - Points to the right of the wire: Magnetic field points into/out of the page.
    - Points above the wire: Magnetic field points into/out of the page.

Calculate the magnitude using Biot-Savart Law or its simplified version for a long straight wire:
\[ B = \frac{\mu_0 I}{2 \pi r} \]
where:
- \( \mu_0 \) is the permeability of free space (\( 4 \pi \times 10^{-7} \) T m/A),
- \( I \) is the current,
- \( r \) is the distance from the wire.
Transcribed Image Text:### Magnetic Field Due to a Current-Carrying Wire A long, straight wire perpendicular to this page carries a current of **4.61 A** directed into the page. Find the magnetic field at the following points, all **10.2 cm** from the wire. #### (a) 10.2 cm to the left of the wire - **Magnitude:** [Text Box] - **Direction:** [Dropdown Menu] #### (b) 10.2 cm directly below the wire - **Magnitude:** [Text Box] - **Direction:** [Dropdown Menu] #### (c) 10.2 cm to the right of the wire - **Magnitude:** [Text Box] - **Direction:** [Dropdown Menu] #### (d) 10.2 cm directly above the wire - **Magnitude:** [Text Box] - **Direction:** [Dropdown Menu] ### Explanation of Magnetic Field Direction The magnetic field around a current-carrying wire follows the right-hand rule. When the thumb of the right hand points in the direction of the current, the fingers curled around the wire point in the direction of the magnetic field: - **Into the page:** Use the right-hand rule. - Points to the left of the wire: Magnetic field points into/out of the page. - Points below the wire: Magnetic field points into/out of the page. - Points to the right of the wire: Magnetic field points into/out of the page. - Points above the wire: Magnetic field points into/out of the page. Calculate the magnitude using Biot-Savart Law or its simplified version for a long straight wire: \[ B = \frac{\mu_0 I}{2 \pi r} \] where: - \( \mu_0 \) is the permeability of free space (\( 4 \pi \times 10^{-7} \) T m/A), - \( I \) is the current, - \( r \) is the distance from the wire.
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