A long shunt compound Generator supplies 10 kW at a terminal voltage of 200 V. The machine parameters are as follows: R₁ = 0.07 , R₂ = 0.1 , Rsh = 120 M. If the total losses percentage are 20% and the torque developed by the prime mover is 119.4 N.m, find the following after drawing the circuit diagram: 1. Overall efficiency and the input power 2. Copper loss, 2. Iron and friction loss, 4. Speed in r.p.m.

A long shunt compound Generator supplies 10 kW at a terminal voltage of 200 V. The machine parameters are as follows: R₁ = 0.07 , R₂ = 0.1 , Rsh = 120 M. If the total losses percentage are 20% and the torque developed by the prime mover is 119.4 N.m, find the following after drawing the circuit diagram: 1. Overall efficiency and the input power 2. Copper loss, 2. Iron and friction loss, 4. Speed in r.p.m.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

(3) A four - pole DC long shunt compound generator with a wave wound armature, having 390 conductors, has to supply a load of 500 lamps each of 100 W at a terminal voltage of 250 V. The flux per pole is 30 mWb. The generator has, Ra = 0-05 22. Rs = 0-01 Q and Rf = 100 2. The iron and rotational losses are 1000 W and 1750 W respectively. a) Determine the total power of the load. b) If half of the lamps are tumed OFF. calculate the required generated voltage, Eg. and the speed of the generator. c) Determine the input power to the generator, when all lights are ON. d) Calculate the efficiency of the generator, when all lights are ON.
Suppose there is a load that needs 120W of power and is located 50ft from a generator with a total resistance of 0.2525 Ohms. The load can be designed to operate at 12V or 120V. Find the voltage drop and power losses in the connecting wire for each voltage and comment on the results.
Kindly solve what is ask and provide complete solution so that I can understand. Also, I want a handwritten solution. Thank you so much!!
Please see attached picture
A 6 pole DC lap wound generator has 38 armature conductors with flux per pole is 42 mWb and the e.m.f generated is 78 V, then the speed of the machine is 48.87 rps O 3.87 rps O 0.39 rps O 48.87 rps When the load on a series generator is decreased, then the flux produced will be increased. Select one: O True O False
4. Two 3300 V star-connected alternators running in parallel supply the following loads : 800 kW at unity p.f.; 600 kW at p.f. 0-8 lagging; 400 kW at p.f. 0-707 lagging The armature current of one machine is 150 A at p.f. 0-85 lagging. What is the armature current, output and p.f. of the other machine? [200 A; 1071 kW; 0-937 lagging]
A lap-winding DC machine has 24 coils, 18 turns per coil, and 4 poles. The average flux density per pole is 1T. The effective length is 40 cm and the armature radius is 10 cm. The armature velocity is 140.2 rad/sec and the armature current is 24 A. The average flux per pole in Wb is: 6.283 0.06283 O 0.6283 0.006283
A D.C. shunt wound generator running at constant speed generates a voltage of 120V at a certain value of field current. When flux is reduced by 10% calculate the new value of flux Estimate the change in the generated voltage when the field current is reduced by 10%, assuming the flux is proportional to the field current.
Please quick solution
Differences between VFD and Soft Starter,include their applications and when are they used.
2MVA, 2.3kV 3Ø Y-connected alternator operates at rated kVA at a power factor of 80%. The DC armature winding resistance between terminals is 0.08Ω. The field takes 70A at 125V from an exciter equipment. Friction and windage loss is 20kW, iron losses 36kW and stray load losses are 2kW. Calculate the efficiency of the alternator. Assume the effective armature winding resistance is 120% of the DC resistance.
A shunt generator delivers 195 A at a terminal voltage of 250 V. The armature resistance and the shunt field resistance are 0.02 and 0.05 ohm respectively. The iron and the friction losses are equal to 950 W. Find the electrical efficiency.