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A long coaxial cable has an inner conductor with radius a and outer conductor with radius b. If the inner conductor has p. = po/p, where po is a constant, determine E everywhere.

A long coaxial cable has an inner conductor with radius a and outer conductor with radius b. If the inner conductor has p. = po/p, where po is a constant, determine E everywhere.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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 The attached pictures below are the question and solution to ask. I don't know why E is 0 when r<a. Please explain this part.

A long coaxial cable has an inner conductor with radius a and outer conductor with radius b. If the inner conductor has p. = po/p, where po is a constant, determine E everywhere.
Transcribed Image Text:A long coaxial cable has an inner conductor with radius a and outer conductor with radius b. If the inner conductor has p. = po/p, where po is a constant, determine E everywhere.
Using Gauss' law, when p<a, =E For a <p<b, Qenc = [ƒ D • dS =¤¸ ƒ¸ E • dS =ɛ¸Ê¸(2ñµL) where L is the length of the cable. But 2π ι Qonc = [p¸ds = ₁ ººpdødz = p¸2ñL S S р p=0 z=0 р2лL=εE (2лрL) For p>b, Qenc = 0. Thus, Po aps a<p<b E=&P E = 0 0, otherwise E = Po & p
Transcribed Image Text:Using Gauss' law, when p<a, =E For a <p<b, Qenc = [ƒ D • dS =¤¸ ƒ¸ E • dS =ɛ¸Ê¸(2ñµL) where L is the length of the cable. But 2π ι Qonc = [p¸ds = ₁ ººpdødz = p¸2ñL S S р p=0 z=0 р2лL=εE (2лрL) For p>b, Qenc = 0. Thus, Po aps a<p<b E=&P E = 0 0, otherwise E = Po & p
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