a) Locate the X' centroidal axes for the areas shown with the respect to the reference axis shown below. b) Calculate the moment of inertia around the X'-Centroidal axis found in part a. Make sure you show all the shapes used, locate their local centroidal axis and show the X' centroidal axis on the sketch below. Solve part a and b using tables on the following page as shown in class. Axis of Reference. 30 mm 15 mm 50 mm

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Use the chart method to solve and show work in organized mannner. write out steps 

a) Locate the X' centroidal axes for the areas shown with the respect to the reference axis
shown below.
b) Calculate the moment of inertia around the X'-Centroidal axis found in part a.
Make sure you show all the shapes used, locate their local centroidal axis and show the X'
centroidal axis on the sketch below. Solve part a and b using tables on the following page as
shown in class.
Axis of Reference.
30 mm
15 mm
50 mm
Transcribed Image Text:a) Locate the X' centroidal axes for the areas shown with the respect to the reference axis shown below. b) Calculate the moment of inertia around the X'-Centroidal axis found in part a. Make sure you show all the shapes used, locate their local centroidal axis and show the X' centroidal axis on the sketch below. Solve part a and b using tables on the following page as shown in class. Axis of Reference. 30 mm 15 mm 50 mm
Centroids locations and Moment of Inertia for simple geometric shape
a
CG
b
A=bh
I₁=
bh³
12
hb³
12
h
x
x=y=4
лd²
4
A=
1,-1,-10²
64
CG
b k
A=
bh
2
bh³
36
I₂ =
h
y=
3
b +
X=
A=
CG
a+b
3
bh
2
I₂ =
bh³
36
h
y=
y=
2 d
3r
CG
πd²
8
Jd4
I₂ = 1
128
d
лdª
128
145.78
HEL
8
3π
x
d/2
A=
x=p=-
πα
2d
3π
16
I₁=I₂
➜
d4
291.4
Transcribed Image Text:Centroids locations and Moment of Inertia for simple geometric shape a CG b A=bh I₁= bh³ 12 hb³ 12 h x x=y=4 лd² 4 A= 1,-1,-10² 64 CG b k A= bh 2 bh³ 36 I₂ = h y= 3 b + X= A= CG a+b 3 bh 2 I₂ = bh³ 36 h y= y= 2 d 3r CG πd² 8 Jd4 I₂ = 1 128 d лdª 128 145.78 HEL 8 3π x d/2 A= x=p=- πα 2d 3π 16 I₁=I₂ ➜ d4 291.4
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