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A local bottling company has determined the number of machine breakdowns per month and their respective probabilities as shown below. Number of Breakdowns Probability .12 1 38 2 25 18 4 .07 16. Refer to Exhibit 5-4. The probability of at least 3 breakdowns in a month is .5 .10 .25 .30

A local bottling company has determined the number of machine breakdowns per month and their respective probabilities as shown below. Number of Breakdowns Probability .12 1 38 2 25 18 4 .07 16. Refer to Exhibit 5-4. The probability of at least 3 breakdowns in a month is .5 .10 .25 .30

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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A local bottling company has determined the number of machine breakdowns per month and their respective probabilities as shown below. | Number of Breakdowns | Probability | |----------------------|-------------| | 0 | 0.12 | | 1 | 0.38 | | 2 | 0.25 | | 3 | 0.18 | | 4 | 0.07 | Question 16: Refer to Exhibit 5-4. The probability of at least 3 breakdowns in a month is ______. Options: - 0.5 - 0.10 - 0.25 - 0.30 (selected answer) In the given probability distribution, the probabilities for having 3 or more breakdowns (i.e., 3 or 4 breakdowns) in a month are: - 3 breakdowns: 0.18 - 4 breakdowns: 0.07 The probability of at least 3 breakdowns is calculated as the sum of these probabilities: 0.18 + 0.07 = 0.25. However, the selected answer is 0.30.
Transcribed Image Text:A local bottling company has determined the number of machine breakdowns per month and their respective probabilities as shown below. | Number of Breakdowns | Probability | |----------------------|-------------| | 0 | 0.12 | | 1 | 0.38 | | 2 | 0.25 | | 3 | 0.18 | | 4 | 0.07 | Question 16: Refer to Exhibit 5-4. The probability of at least 3 breakdowns in a month is ______. Options: - 0.5 - 0.10 - 0.25 - 0.30 (selected answer) In the given probability distribution, the probabilities for having 3 or more breakdowns (i.e., 3 or 4 breakdowns) in a month are: - 3 breakdowns: 0.18 - 4 breakdowns: 0.07 The probability of at least 3 breakdowns is calculated as the sum of these probabilities: 0.18 + 0.07 = 0.25. However, the selected answer is 0.30.
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