A local bottler in Hawaii wishes to ensure that an average of 10 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 39 bottles. The mean weight of the passion fruit juice in the sample is 9.54 ounces. Assume that the population standard deviation is 1.25 ounce. (You may find it useful to reference the appropriate table: z table or t table) Select the null and the alternative hypotheses to test if the bottling process is inaccurate. multiple choice 1 H0: μ = 10; HA: μ ≠ 10
A local bottler in Hawaii wishes to ensure that an average of 10 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 39 bottles. The mean weight of the passion fruit juice in the sample is 9.54 ounces. Assume that the population standard deviation is 1.25 ounce. (You may find it useful to reference the appropriate table: z table or t table)
- Select the null and the alternative hypotheses to test if the bottling process is inaccurate.
multiple choice 1
- H0: μ = 10; HA: μ ≠ 10
- H0: μ ≤ 10; HA: μ > 10
- H0: μ ≥ 10; HA: μ < 10
b-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.)
b-2. Find the p-value.
- 0.05 p-value < 0.10
- p-value 0.10
- p-value < 0.01
- 0.01 p-value < 0.025
- 0.025 p-value < 0.05
c-1. What is the conclusion at α = 0.01?
- Do not reject H0 since the p-value is less than the significance level.
- Do not reject H0 since the p-value is greater than the significance level.
- Reject H0 since the p-value is less than the significance level.
- Reject H0 since the p-value is greater than the significance level.
c-2. Make a recommendation to the bottler.
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