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A liquid phase rxn A + S → P undergoes an isochoric process in a Continuously Stirred Tank Reactor and follows the rate law given below. Derive the expression in order to get the Damkohler No., as a function of reactant A's conversion (XA). Liter 0.2 moles hour Given CÃO = 1 moles/liter, k₁ = 0. 25- Damkohler No = 10. From the given values, -TA k₂ = 0.10 (Liters/mole)², determine the conversion. 1.2 k₁CA 1+k₂CA 2

A liquid phase rxn A + S → P undergoes an isochoric process in a Continuously Stirred Tank Reactor and follows the rate law given below. Derive the expression in order to get the Damkohler No., as a function of reactant A's conversion (XA). Liter 0.2 moles hour Given CÃO = 1 moles/liter, k₁ = 0. 25- Damkohler No = 10. From the given values, -TA k₂ = 0.10 (Liters/mole)², determine the conversion. 1.2 k₁CA 1+k₂CA 2

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Topic: Constant Temperature Continuously Stirred Tank Reactor

A liquid phase rxn A + S → P undergoes an isochoric process in a Continuously Stirred Tank Reactor and follows the rate law given below. Derive the expression in order to get the Damkohler No., as a function of reactant A's conversion (XA). 0.2 Liter moles Given CÃO = 1 moles/liter, k, = 0. 25- hour = 0.10 (Liters/mole)², -, k₂² Damkohler No = 10. From the given values, determine the conversion. -TA = 1.2 k₁CA¹ 1+k₂CA
Transcribed Image Text:A liquid phase rxn A + S → P undergoes an isochoric process in a Continuously Stirred Tank Reactor and follows the rate law given below. Derive the expression in order to get the Damkohler No., as a function of reactant A's conversion (XA). 0.2 Liter moles Given CÃO = 1 moles/liter, k, = 0. 25- hour = 0.10 (Liters/mole)², -, k₂² Damkohler No = 10. From the given values, determine the conversion. -TA = 1.2 k₁CA¹ 1+k₂CA
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