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A liquid food (Cp = 4.0 kJ/kg oC) flows in the inner pipe of a double-pipe heat exchanger. The liquid food enters the heat exchanger at 20oC and exits at 60oC. The flow rate (M) of the liquid food is 0.5 kg/s. In the annular section, hot water at 90oC enters the heat exchanger and flows counter currently at a flow rate (M) of 1 kg/s. The average specific heat (Cp) of water is 4.18 kJ/kg oC. Assume steady state conditions.   1) Calculate the exit temperature of water. Use the following equation: M(cold) Cp ΔT = M(hot) Cp ΔT   2) Calculate LMTD (Logarithmic Mean Temperature Difference). Use the following equation: LMTD = (ΔT1 – ΔT2) / ln((ΔT1) / (ΔT2))   3) If the average overall heat transfer coefficient (U) is 2000 W/m2oC and the diameter of the inner pipe is 5 cm, calculate the length (L) of the heat exchanger. Use the following: Q= M Cp ΔT(food)​Area = Pi * D * L ​Q= U * A * LMTD => Q / (U * MTD) = A

A liquid food (Cp = 4.0 kJ/kg oC) flows in the inner pipe of a double-pipe heat exchanger. The liquid food enters the heat exchanger at 20oC and exits at 60oC. The flow rate (M) of the liquid food is 0.5 kg/s. In the annular section, hot water at 90oC enters the heat exchanger and flows counter currently at a flow rate (M) of 1 kg/s. The average specific heat (Cp) of water is 4.18 kJ/kg oC. Assume steady state conditions.   1) Calculate the exit temperature of water. Use the following equation: M(cold) Cp ΔT = M(hot) Cp ΔT   2) Calculate LMTD (Logarithmic Mean Temperature Difference). Use the following equation: LMTD = (ΔT1 – ΔT2) / ln((ΔT1) / (ΔT2))   3) If the average overall heat transfer coefficient (U) is 2000 W/m2oC and the diameter of the inner pipe is 5 cm, calculate the length (L) of the heat exchanger. Use the following: Q= M Cp ΔT(food)​Area = Pi * D * L ​Q= U * A * LMTD => Q / (U * MTD) = A

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A liquid food (Cp = 4.0 kJ/kg oC) flows in the inner pipe of a double-pipe heat exchanger. The liquid food enters the heat exchanger at 20oC and exits at 60oC. The flow rate (M) of the liquid food is 0.5 kg/s. In the annular section, hot water at 90oC enters the heat exchanger and flows counter currently at a flow rate (M) of 1 kg/s. The average specific heat (Cp) of water is 4.18 kJ/kg oC. Assume steady state conditions.

 

1) Calculate the exit temperature of water. Use the following equation:

M(cold) Cp ΔT = M(hot) Cp ΔT

 

2) Calculate LMTD (Logarithmic Mean Temperature Difference). Use the following equation: LMTD = (ΔT1 – ΔT2) / ln((ΔT1) / (ΔT2))

 

3) If the average overall heat transfer coefficient (U) is 2000 W/m2oC and the diameter of the inner pipe is 5 cm, calculate the length (L) of the heat exchanger. Use the following:

Q= M Cp ΔT(food)​Area = Pi * D * L ​Q= U * A * LMTD => Q / (U * MTD) = A

 

 

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