(a) line damage given that there is transformer damage; (b) transformer damage given that there is line damage; (c) transformer damage but not line damage;
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1. In studying the causes of power failures, these data have been gathered.
5% are due to transformer damage.
80% are due to line damage.
1% involve both problems.
Based on these percentages, approximate the probability that a given power failure
involves:
(a) line damage given that there is transformer damage;
(b) transformer damage given that there is line damage;
(c) transformer damage but not line damage;
(d) transformer damage given that there is no line damage;
(e) transformer damage or line damage.
Step by step
Solved in 4 steps with 3 images
- Question 4. Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the school's career center. X 1 2 3 4 7 P(X) 0.002 0.011 0.115 0.123 0.144 0.189 0.238 0.178 We collect a random sample of 1000 college seniors who complete job applications through the career center. Part a) Based on the probability distribution, which result would be surprising? 14 seniors completed 1 job application through the career centers. 15 seniors completed 2 job applications through the career center. 130 seniors completed 3 job applications through the career center.O Question 27 Deandre buys a bag of cookies that contains 4 chocolate chip cookies, 5 peanut butter cookies, 9 sugar cookies and 4 oatmeal raisin cookies. What is the probability that Deandre randomly selects a peanut butter cookie from the bag, eats it, then randomly selects another peanut butter cookie? (Round your answer to 4 decimal places.) Submit QuestionThe data on the right represent the number of live multiple-delivery births (three or more babies) in a particular year for women 15 to 54 years old. Use the data to complete parts (a) through (d) below. Age Number of Multiple Births 15-19 90 20-24 512 25-29 1633 30-34 2839 35-39 1842 40-44 379 45-54 115 (a) Determine the probability that a randomly selected multiple birth for women 15-54 years old involved a mother 30 to 39 years old. P(30 to 39)=0.6320.632 (Type an integer or decimal rounded to three decimal places as needed.) (b) Determine the probability that a randomly selected multiple birth for women 15-54 years old involved a mother who was not 30 to 39 years old. P(not 30 to 39)=nothing (Type an integer or decimal rounded to three decimal places as needed.)
- , 16. A statistically minded fraternity junior keeps records on how many girls he has to ask before one agrees to be his date for a Saturday football game. His school plays five home games and his five acceptances come on the 3rd, 6th, 4th, 2nd, and 9th girl he asks. Assume that the probability, e, that any girl he asks will accept his invitation is constant from girl to girl. Mind ML estimate of e.Recall that Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are the auditor for a very large corporation. The revenue file contains millions of numbers in a large computer data bank. You draw a random sample of n = 226 numbers from this file and r = 87 have a first nonzero digit of 1. Let p represent the population proportion of all numbers in the computer file that have a leading digit of 1. 1) Test the claim that p is more than 0.301. Use α = 0.10. 2) What is the value of the sample test statistic? (Round your answer to two decimal places.) 3) Find the P-value of the test statistic. (Round your answer to four decimal places.) 4) If p is in fact larger than 0.301, it would seem there are too many numbers in…Question 19 The table summarizes results from 976 pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Pedestrian Intoxicated? Driver Intoxicated? Yes No Yes 41 80 No 224 631 If one of the pedestrian deaths is randomly selected, find the probability that neither the pedestrian nor the driver was intoxicated. Please enter a decimal to 4 places. Submit Question
- vm 6.2 10 The table summarizes results from 976 pedestrian deaths that were caused by automobile accidents. DriverIntoxicated? Pedestrian Intoxicated? Yes No Yes 41 85 No 219 631 If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated.Report the answer as a percent rounded to one decimal place accuracy.QUESTION 3 A large chain retailer purchases a certain kind of electronic device from a manufacturer. The manufacturer indicates that the defective rate of the device is 10%. If the inspector of the retailer randomly picks 18 items from a shipment, the probability that there will be at least one defective item among these 18 items is O 0.5497 O 0.1501 O 0.4503 O 0.8499 lick Save and Submit to save and submit. Click Save All Answers to save all answers.Question 1. Compilation of results from a clinical trial reveals that 475 of 601 cases survive at least 5 years after diagnosis. Based on this information, estimate the probability of surviving at least 5 years.a. Probability of surviving at least 5 years is estimated to be 0.79 b. Probability of surviving at least 5 years is estimated to be 0.50c. Probability of surviving at least 5 years is estimated to be 0.21 d. Probability of surviving at least 5 years is estimated to be 1.27
- The helght of all the people in your neighborhood. QUESTION 6 The Sarasota Police department collected data on the number of car accidents ( X ) that occur each day on a certain stretch of route 41. From this data, they derived the probability distribution shown in the table below. P(X) 0.80 1 0.15 0.05 What is the expected mean (average) number of accidents that occur each day? 0.50 0.25 0.33 1.00 Hal Saveand Submit to saue and submit Click Save All Ansm e Type here to search#1. Use Minitab to simulate 1000 rolls of a pair of dice. Find the number of times that the sum of the two dice is exactly 7. Enter that value here. Based on that result, use the relative frequency approach to estimate the probability of getting a 7 when two dice are rolled. Enter the estimated probability here. How does the estimated probability compare to the true probability? (The true probability found using the classical approach to probability is P(7)=.167) Use the classical approach (no Minitab needed) to find the probability for the sum óf the two dice. You can also verify that P(sum of 2 dice = 7) =.167. P(sum of 2 dice = 2) = P(sum of 2 dice = 3) = P(sum of 2 dice = 4) = P(sum of 2 dice = 5) = P(sum of 2 dice = 6) = P(sum of 2 dice = 8) = P(sum of 2 dice = 9) = P(sum of 2 dice = 10) = P(sum of 2 dice = 11) = P(sum of 2 dice = 12) %3D
