A lila m2=1 Kg and initial velocity u2= 10m/s moving to the left as shown in the figure below. Find the velocities (vị and v2) of the two masses after collision assuming a perfectly elastic collision. (Hint: Use both conservation of momentum and conservation of energy). =-10m/s ai =10m/s m2 = TKg M = 0 lomis Ui is along Uz is along tahen as NOTE : threfane take it al -10m/s
A lila m2=1 Kg and initial velocity u2= 10m/s moving to the left as shown in the figure below. Find the velocities (vị and v2) of the two masses after collision assuming a perfectly elastic collision. (Hint: Use both conservation of momentum and conservation of energy). =-10m/s ai =10m/s m2 = TKg M = 0 lomis Ui is along Uz is along tahen as NOTE : threfane take it al -10m/s
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:# Elastic Collision Problem
A mass, \(m_1 = 1 \, \text{Kg}\), with an initial velocity \(u_1 = 10 \, \text{m/s}\) moving to the right, collides with another mass, \(m_2 = 1 \, \text{Kg}\), with an initial velocity \(u_2 = 10 \, \text{m/s}\) moving to the left as shown in the figure below. Find the velocities (\(v_1\) and \(v_2\)) of the two masses after the collision, assuming a perfectly elastic collision. *(Hint: Use both conservation of momentum and conservation of energy).*
## Diagram Explanation
The diagram depicts two blocks on a horizontal line representing the x-axis:
- **Block 1** (left side):
- Labeled \(m_1 = 1 \, \text{kg}\)
- Initially moving to the right with initial velocity \(u_1 = 10 \, \text{m/s}\)
- Arrow pointing right indicates the direction of motion.
- **Block 2** (right side):
- Labeled \(m_2 = 1 \, \text{kg}\)
- Initially moving to the left with initial velocity \(u_2 = -10 \, \text{m/s}\)
- Arrow pointing left indicates the direction of motion.
## Notation and Notes
- There is a coordinate system with x-axis defined horizontally and y-axis vertically.
- A note clarifies:
- \(u_1\) is along the positive x-axis and is taken as \(10 \, \text{m/s}\).
- \(u_2\) is along the negative x-axis and thus is taken as \(-10 \, \text{m/s}\).
This setup requires using the conservation laws to find the final velocities of both masses after the collision.
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