A lila m2=1 Kg and initial velocity u2= 10m/s moving to the left as shown in the figure below. Find the velocities (vị and v2) of the two masses after collision assuming a perfectly elastic collision. (Hint: Use both conservation of momentum and conservation of energy). =-10m/s ai =10m/s m2 = TKg M = 0 lomis Ui is along Uz is along tahen as NOTE : threfane take it al -10m/s

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# Elastic Collision Problem

A mass, \(m_1 = 1 \, \text{Kg}\), with an initial velocity \(u_1 = 10 \, \text{m/s}\) moving to the right, collides with another mass, \(m_2 = 1 \, \text{Kg}\), with an initial velocity \(u_2 = 10 \, \text{m/s}\) moving to the left as shown in the figure below. Find the velocities (\(v_1\) and \(v_2\)) of the two masses after the collision, assuming a perfectly elastic collision. *(Hint: Use both conservation of momentum and conservation of energy).*

## Diagram Explanation

The diagram depicts two blocks on a horizontal line representing the x-axis:

- **Block 1** (left side):  
  - Labeled \(m_1 = 1 \, \text{kg}\)
  - Initially moving to the right with initial velocity \(u_1 = 10 \, \text{m/s}\)
  - Arrow pointing right indicates the direction of motion.

- **Block 2** (right side):  
  - Labeled \(m_2 = 1 \, \text{kg}\)
  - Initially moving to the left with initial velocity \(u_2 = -10 \, \text{m/s}\)
  - Arrow pointing left indicates the direction of motion.

## Notation and Notes

- There is a coordinate system with x-axis defined horizontally and y-axis vertically.
- A note clarifies:
  - \(u_1\) is along the positive x-axis and is taken as \(10 \, \text{m/s}\).
  - \(u_2\) is along the negative x-axis and thus is taken as \(-10 \, \text{m/s}\).

This setup requires using the conservation laws to find the final velocities of both masses after the collision.
Transcribed Image Text:# Elastic Collision Problem A mass, \(m_1 = 1 \, \text{Kg}\), with an initial velocity \(u_1 = 10 \, \text{m/s}\) moving to the right, collides with another mass, \(m_2 = 1 \, \text{Kg}\), with an initial velocity \(u_2 = 10 \, \text{m/s}\) moving to the left as shown in the figure below. Find the velocities (\(v_1\) and \(v_2\)) of the two masses after the collision, assuming a perfectly elastic collision. *(Hint: Use both conservation of momentum and conservation of energy).* ## Diagram Explanation The diagram depicts two blocks on a horizontal line representing the x-axis: - **Block 1** (left side): - Labeled \(m_1 = 1 \, \text{kg}\) - Initially moving to the right with initial velocity \(u_1 = 10 \, \text{m/s}\) - Arrow pointing right indicates the direction of motion. - **Block 2** (right side): - Labeled \(m_2 = 1 \, \text{kg}\) - Initially moving to the left with initial velocity \(u_2 = -10 \, \text{m/s}\) - Arrow pointing left indicates the direction of motion. ## Notation and Notes - There is a coordinate system with x-axis defined horizontally and y-axis vertically. - A note clarifies: - \(u_1\) is along the positive x-axis and is taken as \(10 \, \text{m/s}\). - \(u_2\) is along the negative x-axis and thus is taken as \(-10 \, \text{m/s}\). This setup requires using the conservation laws to find the final velocities of both masses after the collision.
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