A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 754 hours. A random sample of 30 light bulbs has a mean life of 732 hours. Assume the population is normally distributed and the population standard deviation is 62 hours. At a = 0.05, do you have enough evidence to reject the manufacturer's claim? Complete parts (a) through (e).

A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 754 hours. A random sample of 30 light bulbs has a mean life of 732 hours. Assume the population is normally distributed and the population standard deviation is 62 hours. At a = 0.05, do you have enough evidence to reject the manufacturer's claim? Complete parts (a) through (e).

Name: A light bulb manufacturer guarantees that the mean life of a certain
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 754 hours. A random sample of 30 light bulbs has a mean life of 732 hours. Assume the population is normally distributed and thepopulation standard d

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.05 pounds. At a = 0.06, can you reject the claim? Ha: p> 3.1 H3: µs3.1 H, µ#3.3 a (b) Identify the standardized test statistic. z= - 1.59 (Round to two decimal places as needed.) (c) Find the P-value. 0.112 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O B. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. A. Reject Ho- There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.3 pounds. O D. Reject Ho There is not sufficient evidence to reject the claim that mean tuna…
A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 890 kWh. Assume the population standard deviation is 129 kWh. At a = 0.10, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. Ο Α. H0: μ= 870 (claim) Ha:H#870 B. Ho: μ 870 (claim) O C. Ho: H> 890 (claim) Ha: us 890 O D. Ho: H= 890 Ha: u#890 (claim) O E. Ho: H> 870 (claim) ΟΕ H : μ 890 Ha: uS870 Ha: u> 890 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical value is O B. The critical values are +
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
Claim: The standard deviation of pulse rates of adult males is less than 10 bpm. For a random sample of 140 adult males, the pulse rates have a standard deviation of 9.3 bpm.
Help is needed
Babies: A sample of 25 one-year-old girls had a mean weight of 24.1 pounds with a standard deviation of 4.3 pounds. Assume that the population of weights is normally distributed. A pediatrician claims that the standard deviation of the weights of one-year-old girls is greater than 7 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the =α0.05 level of significance.
A distribution of values is normal with a mean of 197.6 and a standard deviation of 24.6.Find P40, which is the score separating the bottom 40% from the top 60 P40 =
Assume that adults have IQ scores that are normally distributed with a mean of 104.5 and a standard deviation 24.7. Find the first quartile Q,. which is the IQ score separating the bottom 25% from the top 75%. (Hint Draw a graph.) The first quartile is (Type an integer or decimal rounded to one decimal place as needed.)
The biologist wants to estimate the average age of Coyotes in Tuolumne County. Her estimates from past experience suggests the standard deviation is 1.3 years. How big of a sample should she take to be 95% sure his estimate is off by no more than 3minutes?
A distributor's average daily customer demand is 400 units. The standard deviation of customer demand is 30 units. If the distributor would like to maintain a 98% service level (Z score = 2.05) and the supplier's lead time is 9 days, how much safety stock should be held? O 123 units O 185 units O 36,000 units O 554 units
A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with μ = 514. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is 520 with a standard deviation of 112. Complete parts (a) through (d) below. to = 1.04 (Round to two decimal places as needed.) Find the P-value. The P-value is (Round to three decimal places as needed.)
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 171 adult males, the mean pulse rate is 70.3 bpm and the standard deviation is 11.4 bpm. Find the value of the test statistic.