A light bulb consumes energy at a rate of 80.0 joules per second. How long in seconds will it take for the light bulb to consume 2.30 x 105 in energy? J

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter1: The Nature Of Chemistry
Section: Chapter Questions
Problem 110QRT
icon
Related questions
Question
100%
Must use dimensional analysis
**Energy Consumption Calculation for a Light Bulb**

**Problem Statement:**
A light bulb consumes energy at a rate of **80.0 joules per second**. How long in **seconds** will it take for the light bulb to consume **2.30 × 10⁵ J** in energy?

---

### Steps to Calculate Time:

1. **Understand the Units:**
   - **Rate of energy consumption (Power):** 80.0 joules per second (J/s)
   - **Total energy consumed (Energy):** 2.30 × 10⁵ joules (J)

2. **Required Formula:**
   - The formula to calculate time when energy and power are known is \( \text{Time} = \frac{\text{Energy}}{\text{Power}} \)
   - Substituting the values:
     \[ \text{Time (seconds)} = \frac{2.30 \times 10^5 \, \text{J}}{80.0 \, \text{J/s}} \]

3. **Units Clarification:**
   - Ensure that energy is in joules (J) and power is in joules per second (J/s) to obtain time in seconds (s).

4. **Calculate:**
   - Performing the division:
     \[ \text{Time} = \frac{2.30 \times 10^5}{80.0} \]
   - This will give the time in seconds required for the light bulb to consume the specified amount of energy.

---

### Interactive Diagram Explanation:

- **Section: Starting Amount**
  - This section is framed to show a setup where initial inputs can be placed to start the calculation process.

- **Calculation Boxes:**
  - A set of empty boxes framed in black parentheses indicates where the numerical inputs and operations will be placed.
  
- **Available Buttons for Calculation:**
  - **Blue Buttons:** Numbers and constants that can be used for calculations, like `1, 1.84 × 10⁷, 2880, 1000, 4.184, 80.0, 3830, 2.30 × 10⁵`.
  - **Red Buttons:** Units of measurement like `min (minutes), s (seconds), J/s (joules per second), kJ (kilojoules), J (joules), kcal (kilocalories
Transcribed Image Text:**Energy Consumption Calculation for a Light Bulb** **Problem Statement:** A light bulb consumes energy at a rate of **80.0 joules per second**. How long in **seconds** will it take for the light bulb to consume **2.30 × 10⁵ J** in energy? --- ### Steps to Calculate Time: 1. **Understand the Units:** - **Rate of energy consumption (Power):** 80.0 joules per second (J/s) - **Total energy consumed (Energy):** 2.30 × 10⁵ joules (J) 2. **Required Formula:** - The formula to calculate time when energy and power are known is \( \text{Time} = \frac{\text{Energy}}{\text{Power}} \) - Substituting the values: \[ \text{Time (seconds)} = \frac{2.30 \times 10^5 \, \text{J}}{80.0 \, \text{J/s}} \] 3. **Units Clarification:** - Ensure that energy is in joules (J) and power is in joules per second (J/s) to obtain time in seconds (s). 4. **Calculate:** - Performing the division: \[ \text{Time} = \frac{2.30 \times 10^5}{80.0} \] - This will give the time in seconds required for the light bulb to consume the specified amount of energy. --- ### Interactive Diagram Explanation: - **Section: Starting Amount** - This section is framed to show a setup where initial inputs can be placed to start the calculation process. - **Calculation Boxes:** - A set of empty boxes framed in black parentheses indicates where the numerical inputs and operations will be placed. - **Available Buttons for Calculation:** - **Blue Buttons:** Numbers and constants that can be used for calculations, like `1, 1.84 × 10⁷, 2880, 1000, 4.184, 80.0, 3830, 2.30 × 10⁵`. - **Red Buttons:** Units of measurement like `min (minutes), s (seconds), J/s (joules per second), kJ (kilojoules), J (joules), kcal (kilocalories
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Thermodynamics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781337398909
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Chemistry: Matter and Change
Chemistry: Matter and Change
Chemistry
ISBN:
9780078746376
Author:
Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:
Glencoe/McGraw-Hill School Pub Co
Physical Chemistry
Physical Chemistry
Chemistry
ISBN:
9781133958437
Author:
Ball, David W. (david Warren), BAER, Tomas
Publisher:
Wadsworth Cengage Learning,
Chemistry In Focus
Chemistry In Focus
Chemistry
ISBN:
9781337399692
Author:
Tro, Nivaldo J.
Publisher:
Cengage Learning,