(a) Let m, n be coprime integers, and suppose a is an integer which is divisible by both m and n. Prove that mn divides a. (b) Show that the conclusion of part (a) is false if m and n are not coprime (i.e., show that if m and n are not coprime, there exists an integer a such that mla and n/a, but mn does not divide a). (c) Show that if hef(x, m) = 1 and hcf(y,m): = = 1, then hcf(xy, m) = 1.
(a) Let m, n be coprime integers, and suppose a is an integer which is divisible by both m and n. Prove that mn divides a. (b) Show that the conclusion of part (a) is false if m and n are not coprime (i.e., show that if m and n are not coprime, there exists an integer a such that mla and n/a, but mn does not divide a). (c) Show that if hef(x, m) = 1 and hcf(y,m): = = 1, then hcf(xy, m) = 1.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![(a) Let m,n be coprime integers, and suppose a is an integer which is
divisible by both m and n. Prove that mn divides a.
(b) Show that the conclusion of part (a) is false if m and n are not coprime
(i.e., show that if m and n are not coprime, there exists an integer a such
that mla and n/a, but mn does not divide a).
(c) Show that if hef(x, m) = 1 and hcf(y,m) = 1, then hcf(xy, m) = 1.
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6389447-1237-4af0-b5c6-eb1260425b55%2F99169157-78b2-48dc-8d85-bf4b92069a9f%2F2qkepaf_processed.png&w=3840&q=75)
Transcribed Image Text:(a) Let m,n be coprime integers, and suppose a is an integer which is
divisible by both m and n. Prove that mn divides a.
(b) Show that the conclusion of part (a) is false if m and n are not coprime
(i.e., show that if m and n are not coprime, there exists an integer a such
that mla and n/a, but mn does not divide a).
(c) Show that if hef(x, m) = 1 and hcf(y,m) = 1, then hcf(xy, m) = 1.
-
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