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A laterally insulated 5-ft long bar is at an initial temperature of f(x) = 60°F. Its thermal diffusivity = 1.3 ft? /hr. From the general solution obtained for the applied cases below, determine the temperature for each case by substituting n = 1, x = 2 ft and t = 1 hr. 1st Case: After preparing the initial condition of the bar, its boundary temperatures are simultaneously adjusted such that Tieft = 70°F and Tright = 150°F.

A laterally insulated 5-ft long bar is at an initial temperature of f(x) = 60°F. Its thermal diffusivity = 1.3 ft? /hr. From the general solution obtained for the applied cases below, determine the temperature for each case by substituting n = 1, x = 2 ft and t = 1 hr. 1st Case: After preparing the initial condition of the bar, its boundary temperatures are simultaneously adjusted such that Tieft = 70°F and Tright = 150°F.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A laterally insulated 5-ft long bar is at an initial temperature of f(x) = 60°F. Its thermal diffusivity = 1.3 ft?/hr. From the general solution obtained for the applied cases below, determine the temperature for each case by substituting n = 1, x = 2 ft and t = 1 hr. 1st Case: After preparing the initial condition of the bar, its boundary temperatures are simultaneously adjusted such that Tieft = 70°F and Tright = 150°F. 2nd Case (IBVP Summary): (Ut = 1.3uxx, 0 < x< 5 ft, t > 0 u(0, t) = 0,ux(5 ft, t) = t > 0 (u(x,0) = 60°F, 0 < x < 5 ft
Transcribed Image Text:A laterally insulated 5-ft long bar is at an initial temperature of f(x) = 60°F. Its thermal diffusivity = 1.3 ft?/hr. From the general solution obtained for the applied cases below, determine the temperature for each case by substituting n = 1, x = 2 ft and t = 1 hr. 1st Case: After preparing the initial condition of the bar, its boundary temperatures are simultaneously adjusted such that Tieft = 70°F and Tright = 150°F. 2nd Case (IBVP Summary): (Ut = 1.3uxx, 0 < x< 5 ft, t > 0 u(0, t) = 0,ux(5 ft, t) = t > 0 (u(x,0) = 60°F, 0 < x < 5 ft
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