Answered: A large wrecking ball is held together… | bartleby

Related questions

Question

A large wrecking ball is held together by two lightweight steel cables. If its mass is 4 090 kg, what is the tension TB in the cable that makes an angle of 40 ° with the vertical?

A) 5.23×10 4 N
B) 194 N
C) 73 N
D) 2×10 3 N

Tb,
Ta
m
E

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

The uniform diving board has a mass of 26 kg. Find the force on the support A when a 69 kg diver stands at the end of the diving board. E 09 m + 3.6 m A
A 2.00 m long horizontal uniform beam of mass 20.0 kg is supported by a wire as shown in the figure. The wire makes an angle of 20.0 degrees with the beam. Attached to the beam 1.40 m from the wall is a ball with a mass of 40 kg. What is the tension in the string? a)1,000 Nb) 1,090 N c) 2,100 N d) 2,250 N e) 2,680 N
26
An archer's bow is drawn at its midpoint until the tension in the string is 0.866 times the force exerted by the archer. What is the angle between the two halves of the string? Number i ! Units ° (degrees)
a meter log is a uniform bar of mass m = 77 kg. You want to support it at a rest parallel to the ground. so you place it on a triangle support at 33 cm mark and tie it with a rope on the ground at the 28 cm mark. A) draw your own configuration out. calculate the tension of the rope ____ N, downward, upward, right, left, or none and support force provided by the triangle support _______ N, downward, upward, right, left, or none b) suppose a gumdrop (point mass mb = 14.00 kg) hangs on to the meter log at the 91 cm mark How large will the tension be on the rope? ______ N conceptually explain why it should increase, decrease, or stay the same, compared to part A. C) Now with everything including the gumdrop, the triangle support has been moved away from the rope, to the end of the meter log.Explain why the system itself cannot stay balanced anymore, and the rope goes (T→0). Calculate: rotational inertia of the system below. I = _______ kg·m2Calculate the sizes (+ only) of both the…
A 0.50-mm-radius fishing line made of nylon is 100 m long when no forces are applied. A fish is hooked and pulls with a tension force Of 250 N. What is the elongation?
22
A 12 000-N shark is supported by a rope attached to a 4.60-m rod that can pivot at the base. (a) Calculate the tension in the cable between the rod and the wall, assuming the cable is holding the system in the position shown in the figure. (Give you answer to three significant digits.) b) Find the horizontal force exerted on the base of the rod magnitude ------- N c) Find the vertical force exerted on the base of the rod. Ignore the weight of the rod. magnitude ------ N
a meter log is a uniform bar of mass m = 77 kg. You want to support it at a rest parallel to the ground. so you place it on a triangle support at 33 cm mark and tie it with a rope on the ground at the 28 cm mark. A) draw your own configuration out. calculate the tension of the rope ____ N, downward, upward, right, left, or none and support force provided by the triangle support _______ N, downward, upward, right, left, or none b) suppose a gumdrop (point mass mb = 14.00 kg) hangs on to the meter log at the 91 cm mark How large will the tension be on the rope? ______ N conceptually explain why it should increase, decrease, or stay the same, compared to part A. C) Now with everything including the gumdrop, the triangle support has been moved away from the rope, to the end of the meter log.Explain why the system itself cannot stay balanced anymore, and the rope goes (T→0). Calculate: rotational inertia of the system below. I = _______ kg·m2Calculate the sizes (+ only) of both the…