A large corporation employs 37525 individuals. The average income of all employees is $76294, with a standard deviation of $17726 and is skewed to the right. Consider this to be the population distribution. You are given a data set consisting of the incomes of 140 randomly selected employees. The population mean is μ=μ=  The population standard deviation is σ=σ=  The sample size is n=n=  Since the sample size is relatively large, the Central Limit Theorem tells us that the sample averages should have a sampling distribution that is (skewed to the rightapproximately normal). The sampling distribution of the sample means is centered at the (populationsample) mean. The sampling distribution has a standard deviation of SD=σ√n=SD=σn= . Round to two decimal places.

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Chapter1: Combinatorial Analysis
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A large corporation employs 37525 individuals. The average income of all employees is $76294, with a standard deviation of $17726 and is skewed to the right. Consider this to be the population distribution.

You are given a data set consisting of the incomes of 140 randomly selected employees.

  • The population mean is μ=μ= 
  • The population standard deviation is σ=σ= 
  • The sample size is n=n= 
  • Since the sample size is relatively large, the Central Limit Theorem tells us that the sample averages should have a sampling distribution that is (skewed to the rightapproximately normal).
  • The sampling distribution of the sample means is centered at the (populationsample) mean.
  • The sampling distribution has a standard deviation of SD=σ√n=SD=σn= . Round to two decimal places.
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