A large aquarium is cylindrical and is 25 feet deep. It can hold 26,667 cu.ft of water. How wide is the tank? (round to the nearest ft.)

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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SectionP.CT: Test
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**Problem: Calculating the Width of a Cylindrical Aquarium**

A large aquarium is cylindrical and is 25 feet deep. It can hold 26,667 cubic feet (cu.ft) of water. How wide is the tank? (Round to the nearest foot.)

To solve this problem, we need to find the diameter (width) of the cylindrical aquarium.

1. **Understanding the Formula:**
   The volume \( V \) of a cylinder can be calculated using the formula:
   
   \[
   V = \pi r^2 h
   \]

   Where:
   - \( V \) is the volume of the cylinder.
   - \( r \) is the radius of the cylinder’s base.
   - \( h \) is the height (or depth) of the cylinder.
   - \( \pi \) (pi) is a constant approximately equal to 3.14159.

2. **Given Values:**
   - Volume (\( V \)) = 26,667 cubic feet
   - Height (\( h \)) = 25 feet

3. **Substitute the Given Values into the Formula:**
   
   \[
   26,667 = \pi r^2 \times 25
   \]

4. **Solve for \( r^2 \):**
   
   \[
   r^2 = \frac{26,667}{\pi \times 25}
   \]

5. **Calculate \( r^2 \):**
   
   \[
   r^2 = \frac{26,667}{3.14159 \times 25}
   \]
   
   \[
   r^2 = \frac{26,667}{78.53975} \approx 339.1
   \]

6. **Solve for \( r \):**
   
   \[
   r = \sqrt{339.1} \approx 18.4
   \]

7. **Calculate the Diameter (Width):**
   
   The diameter \( d \) is twice the radius:
   
   \[
   d = 2r = 2 \times 18.4 \approx 36.8
   \]

   Rounded to the nearest foot, the width of the tank is approximately 37 feet.

**Answer:**
The width of the cylindrical aquarium is approximately 37 feet.
Transcribed Image Text:**Problem: Calculating the Width of a Cylindrical Aquarium** A large aquarium is cylindrical and is 25 feet deep. It can hold 26,667 cubic feet (cu.ft) of water. How wide is the tank? (Round to the nearest foot.) To solve this problem, we need to find the diameter (width) of the cylindrical aquarium. 1. **Understanding the Formula:** The volume \( V \) of a cylinder can be calculated using the formula: \[ V = \pi r^2 h \] Where: - \( V \) is the volume of the cylinder. - \( r \) is the radius of the cylinder’s base. - \( h \) is the height (or depth) of the cylinder. - \( \pi \) (pi) is a constant approximately equal to 3.14159. 2. **Given Values:** - Volume (\( V \)) = 26,667 cubic feet - Height (\( h \)) = 25 feet 3. **Substitute the Given Values into the Formula:** \[ 26,667 = \pi r^2 \times 25 \] 4. **Solve for \( r^2 \):** \[ r^2 = \frac{26,667}{\pi \times 25} \] 5. **Calculate \( r^2 \):** \[ r^2 = \frac{26,667}{3.14159 \times 25} \] \[ r^2 = \frac{26,667}{78.53975} \approx 339.1 \] 6. **Solve for \( r \):** \[ r = \sqrt{339.1} \approx 18.4 \] 7. **Calculate the Diameter (Width):** The diameter \( d \) is twice the radius: \[ d = 2r = 2 \times 18.4 \approx 36.8 \] Rounded to the nearest foot, the width of the tank is approximately 37 feet. **Answer:** The width of the cylindrical aquarium is approximately 37 feet.
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