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A = L = Find the LU factorization of -2 -3 -4 -10 8 U = 4 x₁ = x₂ = x3 = X4 = 2 2 A∞ N A = LU where -2 1 -4 1 and use FORWARD SUBSTITUTION AND BACKWARD SUBSTITUTION to solve the system -2 -3 2 3 -10 -4 -10 8 10 -40 -2 1 -4 1 -4 3 10 11 -6 -18 2 11 -6 -18 X1 x2 x3 X4 = 90

A = L = Find the LU factorization of -2 -3 -4 -10 8 U = 4 x₁ = x₂ = x3 = X4 = 2 2 A∞ N A = LU where -2 1 -4 1 and use FORWARD SUBSTITUTION AND BACKWARD SUBSTITUTION to solve the system -2 -3 2 3 -10 -4 -10 8 10 -40 -2 1 -4 1 -4 3 10 11 -6 -18 2 11 -6 -18 X1 x2 x3 X4 = 90

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A = and use FORWARD SUBSTITUTION AND BACKWARD SUBSTITUTION to solve the system -10 -40 -4 L = U = Find the LU factorization of -2 -3 2 3 -4 -10 8 10 # -2 1 -4 1 2 11 -6 -18 -2 -3 -4 -10 x1 = x2 = -2 1 -4 A = LU where x3 = X4 = 2 80 + 8 3 10 1 2 11 -6 -18 X1 x2 x3 X4 = 90
Transcribed Image Text:A = and use FORWARD SUBSTITUTION AND BACKWARD SUBSTITUTION to solve the system -10 -40 -4 L = U = Find the LU factorization of -2 -3 2 3 -4 -10 8 10 # -2 1 -4 1 2 11 -6 -18 -2 -3 -4 -10 x1 = x2 = -2 1 -4 A = LU where x3 = X4 = 2 80 + 8 3 10 1 2 11 -6 -18 X1 x2 x3 X4 = 90
Expert Solution
Step 1

Given:

A=-2-323-4-10810-21-41211-6-18

-2-323-4-10810-21-41211-6-18x1x2x3x4=-10-40-490

We have to find the LU factorization and use backward and forward substitution to solve the system.

 

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