A kindergarten class has four left-handed children and eleven right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed. (a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR)= P(RL) = P(LR) = P(LL) = (b) Find the probability distribution function for X. k P(X = k)

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A kindergarten class has four left-handed children and eleven right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X
the number
who are left-handed.
(a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one
is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.)
P(RR)=
P(RL):
P(LR)
P(LL)
%D
(b) Find the probability distribution function for X.
k
1
P(X = k)
%3D
Transcribed Image Text:A kindergarten class has four left-handed children and eleven right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X the number who are left-handed. (a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.) P(RR)= P(RL): P(LR) P(LL) %D (b) Find the probability distribution function for X. k 1 P(X = k) %3D
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