A jar contains 34 red marbles numbered 1 to 34 and 42 blue marbles numbered 1 to 42. A marble is drawn at random from the jar. Find the probability of the given event. Please enter reduced fractions. (a) The marble is red. P(red)=    (b) The marble is odd-numbered. P(odd)=    (c) The marble is red or odd-numbered. P(red or odd) =

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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A jar contains 34 red marbles numbered 1 to 34 and 42 blue marbles numbered 1 to 42. A marble is drawn at random from the jar. Find the probability of the given eventPlease enter reduced fractions.

(a) The marble is red. P(red)=   

(b) The marble is odd-numbered. P(odd)=   

(c) The marble is red or odd-numbered. P(red or odd) =   

(d) The marble is blue or even-numbered. P(blue or even) =

Expert Solution
Step 1

Since we only answer up to 3 sub-parts, we’ll answer the first 3. 
Please resubmit the question and specify the other subparts (up to 3) you’d like answered.

 

There are 34 red marbles and 42 blue marbles. So total (34+42)=76 marbles. 

a) P(red)=   n(red marbles)n(all marbles)=3476=1738

 

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