A J-shaped tube is filled with air at 760 Torr and 22 °C. The long arm is closed off at the top and is 100.0 cm long; the short arm is 40.00 cm high. Mercury is poured through a funnel into the open end. When the mercury spills over the top of the short arm, what is the pressure on the trapped air? Let h be the length of mercury in the long arm.
I've posted the below question earlier, and I received the answer. This is the question:
A J-shaped tube is filled with air at 760 Torr and 22 °C. The long arm is closed off at the top and is 100.0 cm long; the short arm is 40.00 cm high. Mercury is poured through a funnel into the open end. When the mercury spills over the top of the short arm, what is the pressure on the trapped air? Let h be the length of mercury in the long arm.
I need further explanation of one step:
- when P2 is obtained in the short arm, the equation is 40-h+P1
1. How did we get this equation?
2. the short arm does not contain any air, why do we create an equation of P2 in the short arm?
Please clarify these concerns.
I have received the answer shown in the attached picture but it is not correct.
![fill
then ain staks comporening.
when we
merey
we con offune tael the totol lengtn = l00+40
fore undestonding
=14omm
in 140 mm of leg tn
Pressme = 10139 6-16 Pa
NG menuny leg fn for air =
is filled so the remaining
6o mm
Asseomiy the area of tube is costunt so Volume od leg to (y
for cir( Gtsumed os am ideol goø ; ot scme temperetume → pV=c)
Pi= itial ain1
pressine
2 -finsl ain
presine
pd Ź
P2
Pi
140x 101396.16
60
Pz
%3D
P2- 236591.04 Pa](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc84f9064-a36f-4a8e-8b23-ed9d26a34575%2F2d36543c-376a-4704-833c-4289058d777b%2Flstj34b_processed.jpeg&w=3840&q=75)
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