А J KMnOд, ОН, heat B Br2 Br2 H29 1) ВНз C 2) H2О2, ОН" HBr, H2O2 Оз, Zn 1) Hg(ОАc)2, СH3ОН 2) NaBH4 CH212, Zn m-СРВА OsO4 G E F

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Chemical Reaction Pathways of an Epoxide

This diagram displays various reaction pathways of a cyclohexene oxide, illustrating the different products that can result from various reagents and reaction conditions.

#### Pathway A:
- **Reagents:** KMnO₄, OH⁻, heat
- **Product:** The double bond is oxidized, leading to cleavage of the double bond and formation of diol.

#### Pathway B:
- **Reagents:** Br₂ 
- **Product:** The double bond reacts with bromine to form a dibromo compound.

#### Pathway C:
- **Reagents:** HBr, H₂O₂
- **Product:** The double bond undergoes anti-Markovnikov addition in the presence of HBr and H₂O₂, resulting in the addition of HBr across the double bond.

#### Pathway D:
- **Reagents:** 1) Hg(OAc)₂, CH₃OH; 2) NaBH₄
- **Product:** This is an oxymercuration-demercuration reaction that adds an -OCH₃ group and an H across the double bond. 

#### Pathway E:
- **Reagents:** m-CPBA
- **Product:** The double bond reacts with meta-chloroperoxybenzoic acid to form an epoxide.

#### Pathway F:
- **Reagents:** OsO₄
- **Product:** The double bond reacts with osmium tetroxide to form a cis-diol.

#### Pathway G:
- **Reagents:** CH₂I₂, Zn
- **Product:** The double bond reacts to form a cyclopropane ring.

#### Pathway H:
- **Reagents:** O₃, Zn
- **Product:** The double bond is cleaved by ozonolysis to form aldehyde or ketone fragments.

#### Pathway I:
- **Reagents:** 1) BH₃; 2) H₂O₂, OH⁻ 
- **Product:** The double bond is converted into an alcohol with anti-Markovnikov orientation through hydroboration-oxidation.

#### Pathway J:
- **Reagent:** Br₂, H₂O
- **Product:** Bromohydrin is formed when the double bond reacts with bromine in an aqueous solution.

Each of these pathways demonstrates a distinct type of chemical reaction, showcasing the versatility of organic synthesis methods
Transcribed Image Text:### Chemical Reaction Pathways of an Epoxide This diagram displays various reaction pathways of a cyclohexene oxide, illustrating the different products that can result from various reagents and reaction conditions. #### Pathway A: - **Reagents:** KMnO₄, OH⁻, heat - **Product:** The double bond is oxidized, leading to cleavage of the double bond and formation of diol. #### Pathway B: - **Reagents:** Br₂ - **Product:** The double bond reacts with bromine to form a dibromo compound. #### Pathway C: - **Reagents:** HBr, H₂O₂ - **Product:** The double bond undergoes anti-Markovnikov addition in the presence of HBr and H₂O₂, resulting in the addition of HBr across the double bond. #### Pathway D: - **Reagents:** 1) Hg(OAc)₂, CH₃OH; 2) NaBH₄ - **Product:** This is an oxymercuration-demercuration reaction that adds an -OCH₃ group and an H across the double bond. #### Pathway E: - **Reagents:** m-CPBA - **Product:** The double bond reacts with meta-chloroperoxybenzoic acid to form an epoxide. #### Pathway F: - **Reagents:** OsO₄ - **Product:** The double bond reacts with osmium tetroxide to form a cis-diol. #### Pathway G: - **Reagents:** CH₂I₂, Zn - **Product:** The double bond reacts to form a cyclopropane ring. #### Pathway H: - **Reagents:** O₃, Zn - **Product:** The double bond is cleaved by ozonolysis to form aldehyde or ketone fragments. #### Pathway I: - **Reagents:** 1) BH₃; 2) H₂O₂, OH⁻ - **Product:** The double bond is converted into an alcohol with anti-Markovnikov orientation through hydroboration-oxidation. #### Pathway J: - **Reagent:** Br₂, H₂O - **Product:** Bromohydrin is formed when the double bond reacts with bromine in an aqueous solution. Each of these pathways demonstrates a distinct type of chemical reaction, showcasing the versatility of organic synthesis methods
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