a) IR(s) = 3s s2 + 200 s + 6400 %D A b) IR(s) = -0,1875 s- 6 A s2 + 200 s + 6400 0,25 s2 + 56 s + 1600 A s (s2 + 200 s + 6400 ) c) IR(s) = %3D

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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After the switches are open for a long time, t=0 is going to be closed. What is the laplace of ir(t) chances?

3 s
a) IR(s) =
A
s2 + 200 s + 6400
-0,1875 s - 6
b) IR(s) =
A
s2 + 200 s + 6400
0,25 s2 + 56 s + 1600
A
s (s² + 200 s + 6400 )
c) IR(s) =
0,0625 s2 + 50 s +1600
A
s (s? + 200 s + 6400 )
d) IR (s) =
s2 + 800 s +25600
e) IR(s) =
A
s (s2 + 200 s + 6400 )
Transcribed Image Text:3 s a) IR(s) = A s2 + 200 s + 6400 -0,1875 s - 6 b) IR(s) = A s2 + 200 s + 6400 0,25 s2 + 56 s + 1600 A s (s² + 200 s + 6400 ) c) IR(s) = 0,0625 s2 + 50 s +1600 A s (s? + 200 s + 6400 ) d) IR (s) = s2 + 800 s +25600 e) IR(s) = A s (s2 + 200 s + 6400 )
16 0
t = 0
4 V
0.5 H
312.5 µF
vo
R = 16 N, L= 0,5 H,
C = 312,5 µF
Transcribed Image Text:16 0 t = 0 4 V 0.5 H 312.5 µF vo R = 16 N, L= 0,5 H, C = 312,5 µF
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