(a) In the accompanying figure, the area of the triangle ABC can be expressed as area ABC = area ADEC + area CEFB - area ADFB C, ya) B(x, y2) Use this and the fact that the area of a trapezoid equals 1 -the altitude times the sum of the parallel sides to show that X1 yı 1 D E F area ABC = X2 y2 1 2 |x3 y3 1 Note In the derivation of this formula, the vertices are labeled such that the triangle is traced counterclockwise proceeding from (x1, Ya) to (x2, y2) to (x3.Y3) . For a clockwise orientation, the determinant above yields the negative of the area. (You should not solve (a) (b) Use the result in (a) to find the area of the triangle with vertices (-5,-2),(4,0), (3,3). Area = i

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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(a)
In the accompanying figure, the area of the triangle ABC can be expressed as
C, y3)
area ABC = area ADEC + area CEFB - area ADFB
B(x, y2)
Use this and the fact that the area of a trapezoid equals
- the altitude times the sum of the parallel
A(x. y)
sides to show that
X1 yı 1
1
D
E
F
area ABC =
x2 y2 1
|x3 y3 1
Note In the derivation of this formula, the vertices are labeled such that the triangle is traced counterclockwise proceeding from (x1,
Ya) to (x2, y2) to (x3.Y3) . For a clockwise orientation, the determinant above yields the negative of the area.
(You should not solve (a))
(b) Use the result in (a) to find the area of the triangle with vertices (-5,-2),(4,0), (3,3).
Area = i
Transcribed Image Text:(a) In the accompanying figure, the area of the triangle ABC can be expressed as C, y3) area ABC = area ADEC + area CEFB - area ADFB B(x, y2) Use this and the fact that the area of a trapezoid equals - the altitude times the sum of the parallel A(x. y) sides to show that X1 yı 1 1 D E F area ABC = x2 y2 1 |x3 y3 1 Note In the derivation of this formula, the vertices are labeled such that the triangle is traced counterclockwise proceeding from (x1, Ya) to (x2, y2) to (x3.Y3) . For a clockwise orientation, the determinant above yields the negative of the area. (You should not solve (a)) (b) Use the result in (a) to find the area of the triangle with vertices (-5,-2),(4,0), (3,3). Area = i
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