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a) In question 1 you were told that the 25 kg block would go down the ramp while the 32 kg block would go up. But if you weren't told that, you would still know that is what must happen. How do we know that the 25 kg block accelerate down and not the 32 kg block? b) If a block of 10 kg is sitting on the floor, its weight is 98.1 N. What principle of physics tells us that the normal force of the floor on the block is also 98.1 N? Explain clearly how it applies in this case. c) What principle of physics tells us that the block in part b) also exerts a force of 9.81 N down on the floor? Again, explain clearly how it applies in this case. d) A car making a turn without speeding up or slowing down still requires a net force on it in order to make the turn. Why isn’t the net force zero if the car is moving at constant speed? e) When calculating the net torque on an object, we can ignore any forces that are exerted at the pivot point. Why is that?

a) In question 1 you were told that the 25 kg block would go down the ramp while the 32 kg block would go up. But if you weren't told that, you would still know that is what must happen. How do we know that the 25 kg block accelerate down and not the 32 kg block? b) If a block of 10 kg is sitting on the floor, its weight is 98.1 N. What principle of physics tells us that the normal force of the floor on the block is also 98.1 N? Explain clearly how it applies in this case. c) What principle of physics tells us that the block in part b) also exerts a force of 9.81 N down on the floor? Again, explain clearly how it applies in this case. d) A car making a turn without speeding up or slowing down still requires a net force on it in order to make the turn. Why isn’t the net force zero if the car is moving at constant speed? e) When calculating the net torque on an object, we can ignore any forces that are exerted at the pivot point. Why is that?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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a) In question 1 you were told that the 25 kg block would go down the ramp while the 32 kg block would go up. But if you weren't told that, you would still know that is what must happen. How do we know that the 25 kg block accelerate down and not the 32 kg block? b) If a block of 10 kg is sitting on the floor, its weight is 98.1 N. What principle of physics tells us that the normal force of the floor on the block is also 98.1 N? Explain clearly how it applies in this case. c) What principle of physics tells us that the block in part b) also exerts a force of 9.81 N down on the floor? Again, explain clearly how it applies in this case. d) A car making a turn without speeding up or slowing down still requires a net force on it in order to make the turn. Why isn’t the net force zero if the car is moving at constant speed? e) When calculating the net torque on an object, we can ignore any forces that are exerted at the pivot point. Why is that?
Transcribed Image Text:a) In question 1 you were told that the 25 kg block would go down the ramp while the 32 kg block would go up. But if you weren't told that, you would still know that is what must happen. How do we know that the 25 kg block accelerate down and not the 32 kg block? b) If a block of 10 kg is sitting on the floor, its weight is 98.1 N. What principle of physics tells us that the normal force of the floor on the block is also 98.1 N? Explain clearly how it applies in this case. c) What principle of physics tells us that the block in part b) also exerts a force of 9.81 N down on the floor? Again, explain clearly how it applies in this case. d) A car making a turn without speeding up or slowing down still requires a net force on it in order to make the turn. Why isn’t the net force zero if the car is moving at constant speed? e) When calculating the net torque on an object, we can ignore any forces that are exerted at the pivot point. Why is that?
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