(a) In order to estimate the thermal expansion of a metal, measurements of the change of length for a known change of temperature are taken by a group of students. A sample random of size 36 is drawn with mean of 15.32 x 10-4 m °C-1 and a standard deviation of 0.12 x 10-4 m °C-¹. Determine the 99% confidence interval for population mean of the thermal expansion, correct to two decimal places. [It is given that: Z0.01 = 2.58]
(a) In order to estimate the thermal expansion of a metal, measurements of the change of length for a known change of temperature are taken by a group of students. A sample random of size 36 is drawn with mean of 15.32 x 10-4 m °C-1 and a standard deviation of 0.12 x 10-4 m °C-¹. Determine the 99% confidence interval for population mean of the thermal expansion, correct to two decimal places. [It is given that: Z0.01 = 2.58]
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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![(a)
In order to estimate the thermal expansion of a metal, measurements of the
change of length for a known change of temperature are taken by a group of
students. A sample random of size 36 is drawn with mean of
15.32 x 10-4 m °C-1 and a standard deviation of 0.12 x 10-4 m °C-¹.
Determine the 99% confidence interval for population mean of the thermal
expansion, correct to two decimal places.
[It is given that: Z0.01 = 2.58]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81e03d6c-c953-47c6-a5f9-daf0571ac32a%2F1730f97d-d353-40f2-8b53-ab011c537e99%2Fsnz571p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(a)
In order to estimate the thermal expansion of a metal, measurements of the
change of length for a known change of temperature are taken by a group of
students. A sample random of size 36 is drawn with mean of
15.32 x 10-4 m °C-1 and a standard deviation of 0.12 x 10-4 m °C-¹.
Determine the 99% confidence interval for population mean of the thermal
expansion, correct to two decimal places.
[It is given that: Z0.01 = 2.58]
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