(a) If X is a normal N(2,64) distribution, find k such that P(k ≤ X ≤12) = 0.2957 (b) The random variable T follows a t-distribution with 14 degrees of freedom. Find k such that P(-0.54
(a) If X is a normal N(2,64) distribution, find k such that P(k ≤ X ≤12) = 0.2957 (b) The random variable T follows a t-distribution with 14 degrees of freedom. Find k such that P(-0.54
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 31E
Question

Transcribed Image Text:(a) If X is a normal N(2,64) distribution, find k such that P(k ≤ X ≤12) = 0.2957
(b) The random variable T follows a t-distribution with 14 degrees of freedom. Find
k such that P(-0.54 <T<k) = 0.3
(c) Six independent measurements are taken from a normal population. the sample
has values x₁ = 4, x2 = 5, x3 = 8, x4 = 6, x5 = 5, x6 = 7. Find a 99% confidence
interval for the mean.
(d) The null hypothesis H, is a manufacturer's claim that a galvanized nail produced
has averaged length μo = 2.5 inches. The alternative hypothesis H₁ that the nail
length is μ₁μo. After testing a sample of 51 nails it is found that the sample
average nail length is = 2.3 inches and that the sample standard deviation is
s = 0.3 inches. For significance level a 1%, determine whether or not the
manufacturer's claim should be accepted. Assume that the average nail length μ
is uniformly distributed.
=
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