a) If v is an eigenvector of a linear operator T, corresponding to an eigenvalue A, show that v is also an eigenvector for the linear operator T2, corresponding to eigenvalue 1². (b) Even if a linear operator T has no eigenvectors, the operator T2 may have eigenvec- tors (an example is a rotation through 90° in the plane). Show that if an operator T2 has an eigenvector with a nonnegative eigenvalue λ = μ², then the operator T
a) If v is an eigenvector of a linear operator T, corresponding to an eigenvalue A, show that v is also an eigenvector for the linear operator T2, corresponding to eigenvalue 1². (b) Even if a linear operator T has no eigenvectors, the operator T2 may have eigenvec- tors (an example is a rotation through 90° in the plane). Show that if an operator T2 has an eigenvector with a nonnegative eigenvalue λ = μ², then the operator T
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Hints on the second picture
![**8.**
(a) \( T(T(v)) = T(\lambda v) = \lambda (\lambda v) = \lambda^2 v \).
(b) \( (T^2 - \mu^2) = (T - \mu)(T + \mu) \). If \( v \neq 0 \) is such that \( (T^2 - \mu^2)(v) = 0 \) then either \( (T + \mu)(v) = 0 \) or \( (T - \mu)(w) = 0 \), where \( w = (T + \mu)(v) \) is a nonzero vector. In either case, the operator \( T \) must have an eigenvector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32f77ee0-291c-46d0-b315-80fb2fd096d8%2F7e68ddbb-1aef-4581-8751-030cc0cf82be%2Fhx0581f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**8.**
(a) \( T(T(v)) = T(\lambda v) = \lambda (\lambda v) = \lambda^2 v \).
(b) \( (T^2 - \mu^2) = (T - \mu)(T + \mu) \). If \( v \neq 0 \) is such that \( (T^2 - \mu^2)(v) = 0 \) then either \( (T + \mu)(v) = 0 \) or \( (T - \mu)(w) = 0 \), where \( w = (T + \mu)(v) \) is a nonzero vector. In either case, the operator \( T \) must have an eigenvector.
![**Problem 8.**
**(a)** If \( v \) is an eigenvector of a linear operator \( T \), corresponding to an eigenvalue \( \lambda \), show that \( v \) is also an eigenvector for the linear operator \( T^2 \), corresponding to eigenvalue \( \lambda^2 \).
**(b)** Even if a linear operator \( T \) has no eigenvectors, the operator \( T^2 \) may have eigenvectors (an example is a rotation through 90° in the plane). Show that if an operator \( T^2 \) has an eigenvector with a nonnegative eigenvalue \( \lambda = \mu^2 \), then the operator \( T \) also has an eigenvector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32f77ee0-291c-46d0-b315-80fb2fd096d8%2F7e68ddbb-1aef-4581-8751-030cc0cf82be%2F1512cg8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 8.**
**(a)** If \( v \) is an eigenvector of a linear operator \( T \), corresponding to an eigenvalue \( \lambda \), show that \( v \) is also an eigenvector for the linear operator \( T^2 \), corresponding to eigenvalue \( \lambda^2 \).
**(b)** Even if a linear operator \( T \) has no eigenvectors, the operator \( T^2 \) may have eigenvectors (an example is a rotation through 90° in the plane). Show that if an operator \( T^2 \) has an eigenvector with a nonnegative eigenvalue \( \lambda = \mu^2 \), then the operator \( T \) also has an eigenvector.
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