(a) If the third-order maximum for monochromatic light falling on a double slit is at an angle of 20.7o at what angle (in degrees) is the fourth-order maximum?(b) What is the angle (in degrees) of the fourth minimum?(c) What is the highest-order maximum possible here?

Light from the two slits going the same distance to the screen causes the brilliant fringe in the center, which is known as the zero-order fringe. Light from one slit going half a wavelength further than light from the other slit causes the black fringes on each side of the zero-order fringe. Interference fringe is a bright or dark band created by light beams that are out of phase with one another. The interference fringes produced by all-optical interferometers are what make them work. (a) Path difference for nth bright fringe is: dsinθ=nλ .... (1) For third-order maximum is: dsin20.70=3λ .... (2) For fourth-order maximum is: dsinθ4=4λ .... (3) Divide equation (3) by equation (2). dsinθ4dsin20.7=4λ3λsinθ40.3534=43sinθ4=430.3534θ4=sin-1430.3534θ4=sin-10.4712θ4=28.110 The fourth-order maximum angle is 28.11 degrees. b) For a fourth minimum, dsinθ4=3.5λ .... (4) Divide equation (4) by equation (2) dsinθ4dsin28.11=3.5λ4λsinθ40.1635=3.54sinθ4=3.540.1635θ4=sin-13.540.1635θ4=sin-10.1430θ4=8.220 The fourth-order minimum angle is 8.22 degrees. c) For maximum highest order is: dsin900=nλ .... (5) Divide equation (5) to equation (2) dsin900dsin20.70=nλ3λ10.3534=n3n=30.3534n=8.4 The maximum highest order is 8.

Answered: (a) If the third-order maximum for…

(a) If the third-order maximum for monochromatic light falling on a double slit is at an angle of 20.7°, at what angle (in degrees) is the fourth-örder (b) What is the angle (in degrees) of the fourth minimum? (c) What is the highest-order maximum possible here?