Tutorial ExerciseA 2.0-g particle moving at 5.5 m/s makes a perfectly elastic head-on collision with a resting 1.0-g object.(a) Find the speed of each particle after the collision.(b) Find the speed of each particle after the collision if the stationary particle has a mass of 10 g.(c) Find the final kinetic energy of the incident 2.0-g particle in the situations described in parts (a)and (b).In which case does the incident particle lose more kinetic energy?Step 1The initial velocity of the target object is zero (v2i= 0). Let m, be the mass of the first particle, v,, its initialvelocity, and v2r its final velocity. Let m, be the mass of the target object and vr its final velocity. Fromconservation of momentum before and after the collision, we have the following equation.m V1f + m2v2f = m,V1 + 0For a perfectly elastic head-on collision, we have the following relationship between the objects' final velocitiesand initial velocities derived from conservation of momentum and conservation of kinetic energy.-- ("x- v2)V1i - V2iBecause v2, = 0, we can solve for the final velocity of the second object.V2f = V1f+ V1/Substituting equation (2) above into equation (1) and solving for v,, we havem, - m,Vif =m, + m2Substituting this result into equation (2) and simplifying, we have2m1V2f =\m, + m2(a) If m, = 2.0 g, m, = 1.0 g, and v = 5.5 m/s, thenm, - m21.0 g/5.5Vif =m, + m2m/s) =5.5m/s,%3D3.0 g3.0andms) = (2m145.5\m, + m23.0 gYour response differs from the correct answer by more than 10%. Double check your calculations.3.0m/s.SubmitSkip (you cannot come back)

As pic indicate your answer differs by more than 10% .The values putted in the eqn are correct…

(a) If m, = 2.0 g, m, = 1.0 g, and v = 5.5 m/s, then %3D m-m2 m, + m2. 1.0 g 5.5 5.5 3.0 g m/s) = m/s, 3.0 and 2m, 4 m/s) = 5.5 mi+ m2. 3.0 g Your response differs from the correct answer by more than 10%. Double check your calculations. 3.0 m/s.

(a) If m, = 2.0 g, m, = 1.0 g, and v = 5.5 m/s, then %3D m-m2 m, + m2. 1.0 g 5.5 5.5 3.0 g m/s) = m/s, 3.0 and 2m, 4 m/s) = 5.5 mi+ m2. 3.0 g Your response differs from the correct answer by more than 10%. Double check your calculations. 3.0 m/s.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Units and Dimensions

These are generally defined as the terms which precede or describes the dimensions further. These are also further divided into two parts namely fundamental units and the derived units.

Question

Tutorial Exercise
A 2.0-g particle moving at 5.5 m/s makes a perfectly elastic head-on collision with a resting 1.0-g object.
(a) Find the speed of each particle after the collision.
(b) Find the speed of each particle after the collision if the stationary particle has a mass of 10 g.
(c) Find the final kinetic energy of the incident 2.0-g particle in the situations described in parts (a)
and (b).
In which case does the incident particle lose more kinetic energy?
Step 1
The initial velocity of the target object is zero (v2i
= 0). Let m, be the mass of the first particle, v,, its initial
velocity, and v2r its final velocity. Let m, be the mass of the target object and vr its final velocity. From
conservation of momentum before and after the collision, we have the following equation.
m V1f + m2v2f = m,V1 + 0
For a perfectly elastic head-on collision, we have the following relationship between the objects' final velocities
and initial velocities derived from conservation of momentum and conservation of kinetic energy.
-- ("x- v2)
V1i - V2i
Because v2, = 0, we can solve for the final velocity of the second object.
V2f = V1f+ V1/
Substituting equation (2) above into equation (1) and solving for v,, we have
m, - m,
Vif =
m, + m2
Substituting this result into equation (2) and simplifying, we have
2m1
V2f =
\m, + m2
(a) If m, = 2.0 g, m, = 1.0 g, and v = 5.5 m/s, then
m, - m2
1.0 g/
5.5
Vif =
m, + m2
m/s) =
5.5
m/s,
%3D
3.0 g
3.0
and
ms) = (
2m1
4
5.5
\m, + m2
3.0 g
Your response differs from the correct answer by more than 10%. Double check your calculations.
3.0
m/s.
Submit
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