Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
a If f is an odd function, why is f(x) dx = 0? a Choose the correct answer below. O A. a a a Since f is odd, f is symmetric about the y-axis. Therefore,| f(x) dx = | f(x) dx → f(x) dx - | f(x) dx = 0 → f(x) dx = 0. a - a a a a a ов. Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = - f(x) dx → f(x) dx + f(x) dx = 0 → f(x) dx = 0. a a a C. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = f(x) dx → f(x) dx - dx = 0 → f(x) dx = 0. -a a

a If f is an odd function, why is f(x) dx = 0? a Choose the correct answer below. O A. a a a Since f is odd, f is symmetric about the y-axis. Therefore,| f(x) dx = | f(x) dx → f(x) dx - | f(x) dx = 0 → f(x) dx = 0. a - a a a a a ов. Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = - f(x) dx → f(x) dx + f(x) dx = 0 → f(x) dx = 0. a a a C. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = f(x) dx → f(x) dx - dx = 0 → f(x) dx = 0. -a a

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
See similar textbooks
icon
Related questions
Question
a If f is an odd function, why is | f(x) dx = 0? - a Choose the correct answer below. O A. a a a Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = | f(x) dx → |f(x) dx - f(x) dx = 0 → f(x) dx = 0. %3D - a - a - a a a O B. Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = - f(x) dx → f(x) dx + f(x) dx = 0 – f(x) dx = 0. %3D -a - a - a a a a С. f(x) c dx → | f(x) dx – f(x) dx = 0 → | f(x) dx = 0. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = %3D - a - a -a
Transcribed Image Text:a If f is an odd function, why is | f(x) dx = 0? - a Choose the correct answer below. O A. a a a Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = | f(x) dx → |f(x) dx - f(x) dx = 0 → f(x) dx = 0. %3D - a - a - a a a O B. Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = - f(x) dx → f(x) dx + f(x) dx = 0 – f(x) dx = 0. %3D -a - a - a a a a С. f(x) c dx → | f(x) dx – f(x) dx = 0 → | f(x) dx = 0. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = %3D - a - a -a
a Iff is an odd function, why is | f(x) dx = 0? ... - a 0. O B. a a Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = f(x) dx → | f(x) dx + f(x) dx = 0 → | f(x) dx = 0. - a - a C. a a a Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = | f(x) dx → f(x) dx - f(x) dx =0 → | f(x) dx = 0. a - a - a a a D. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = í(x) dx → f(x) dx + f(x) dx = 0 → f(x) dx = 0. | - a - a 0. a
Transcribed Image Text:a Iff is an odd function, why is | f(x) dx = 0? ... - a 0. O B. a a Since f is odd, f is symmetric about the y-axis. Therefore, f(x) dx = f(x) dx → | f(x) dx + f(x) dx = 0 → | f(x) dx = 0. - a - a C. a a a Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = | f(x) dx → f(x) dx - f(x) dx =0 → | f(x) dx = 0. a - a - a a a D. Since f is odd, f is symmetric about the origin. Therefore, f(x) dx = í(x) dx → f(x) dx + f(x) dx = 0 → f(x) dx = 0. | - a - a 0. a
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt
College Algebra
College Algebra
Algebra
ISBN:
9781938168383
Author:
Jay Abramson
Publisher:
OpenStax
College Algebra
College Algebra
Algebra
ISBN:
9781305115545
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
Intermediate Algebra
Intermediate Algebra
Algebra
ISBN:
9781285195728
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS