(a) Identify the null hypothesis and alternative hypothesis. OA. Ho: H>3.5 H:H≤3.5 OD. Ho: H≤3.1 H₂:μ>3.1 (b) Identify the standardized test statistic. z=(Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. OA. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds. OC. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds. OB. Ho: μ3.5 H₂:μ>3.5 OE. Ho: H=3.5 H₂:μ*3.5 OC. Ho:>3.1 H₂-μ≤3.1 OF. Ho: *3.1 H₂:μ=3.1 OB. Fail to reject Ho. There is sufficient evidence to reject the claim that me tuna consumption is equal to 3.5 pounds. OD. Reject Ho. There is not sufficient evidence to reject the claim that mear tuna consumption is equal to 3.5 pounds.
(a) Identify the null hypothesis and alternative hypothesis. OA. Ho: H>3.5 H:H≤3.5 OD. Ho: H≤3.1 H₂:μ>3.1 (b) Identify the standardized test statistic. z=(Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. OA. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds. OC. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds. OB. Ho: μ3.5 H₂:μ>3.5 OE. Ho: H=3.5 H₂:μ*3.5 OC. Ho:>3.1 H₂-μ≤3.1 OF. Ho: *3.1 H₂:μ=3.1 OB. Fail to reject Ho. There is sufficient evidence to reject the claim that me tuna consumption is equal to 3.5 pounds. OD. Reject Ho. There is not sufficient evidence to reject the claim that mear tuna consumption is equal to 3.5 pounds.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
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![### Tuna Consumption Hypothesis Test
**Scenario**:
A nutritionist claims that the mean tuna consumption by a person is 3.5 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.17 pounds. At \(\alpha = 0.05\), can you reject the claim?
---
**Hypothesis Identification**:
(a) Identify the null hypothesis and alternative hypothesis.
- **Option A**:
- \( H_0 \): \(\mu > 3.5\)
- \( H_a \): \(\mu \leq 3.5\)
- **Option B**:
- \( H_0 \): \(\mu \leq 3.5\)
- \( H_a \): \(\mu > 3.5\)
- **Option C**:
- \( H_0 \): \(\mu > 3.1\)
- \( H_a \): \(\mu \leq 3.1\)
- **Option D**:
- \( H_0 \): \(\mu \leq 3.1\)
- \( H_a \): \(\mu > 3.1\)
- **Option E**:
- \( H_0 \): \(\mu = 3.5\)
- \( H_a \): \(\mu \ne 3.5\)
- **Option F**:
- \( H_0 \): \(\mu = 3.1\)
- \( H_a \): \(\mu \ne 3.1\)
---
**Standardized Test Statistic**:
(b) Identify the standardized test statistic.
\[ z = \frac{\bar{x} - \mu}{\sigma / \sqrt{n}} \]
**Note**: Round to two decimal places as needed.
---
**P-Value Calculation**:
(c) Find the P-value.
**Note**: Round to three decimal places as needed.
---
**Hypothesis Decision**:
(d) Decide whether to reject or fail to reject the null hypothesis.
- **Option A**:
- Fail to reject \( H_0 \). There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds.
- **Option](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe06fe914-1239-47ca-9a69-106db7b604fb%2F49a3178b-832c-4be5-bdb9-0fda8b515439%2Fsv51594_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Tuna Consumption Hypothesis Test
**Scenario**:
A nutritionist claims that the mean tuna consumption by a person is 3.5 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.17 pounds. At \(\alpha = 0.05\), can you reject the claim?
---
**Hypothesis Identification**:
(a) Identify the null hypothesis and alternative hypothesis.
- **Option A**:
- \( H_0 \): \(\mu > 3.5\)
- \( H_a \): \(\mu \leq 3.5\)
- **Option B**:
- \( H_0 \): \(\mu \leq 3.5\)
- \( H_a \): \(\mu > 3.5\)
- **Option C**:
- \( H_0 \): \(\mu > 3.1\)
- \( H_a \): \(\mu \leq 3.1\)
- **Option D**:
- \( H_0 \): \(\mu \leq 3.1\)
- \( H_a \): \(\mu > 3.1\)
- **Option E**:
- \( H_0 \): \(\mu = 3.5\)
- \( H_a \): \(\mu \ne 3.5\)
- **Option F**:
- \( H_0 \): \(\mu = 3.1\)
- \( H_a \): \(\mu \ne 3.1\)
---
**Standardized Test Statistic**:
(b) Identify the standardized test statistic.
\[ z = \frac{\bar{x} - \mu}{\sigma / \sqrt{n}} \]
**Note**: Round to two decimal places as needed.
---
**P-Value Calculation**:
(c) Find the P-value.
**Note**: Round to three decimal places as needed.
---
**Hypothesis Decision**:
(d) Decide whether to reject or fail to reject the null hypothesis.
- **Option A**:
- Fail to reject \( H_0 \). There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.5 pounds.
- **Option
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