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A) I = Consider the solid bounded by the surfaces S : y = Vr – 1, S2 : y + z = 2, S3 : x = 0, S4 : y= 0, S5 : z = 0 whose graphic representation is (the surface S1 that will be the one of interest is highlighted) y+z = 2 y = V- 1 Consider the vector field F (x, y, z) = (xy, y? + 3z, sin (z)). When calculating I = l. F * nds is obtained: cy²+1 I = (у — 6уг — у) dardy r2 2-y | (y3 + y, y? + 3z, sin(z) · V1+ 4y² dzdy Jo Jo В) I %3 c2 (2-y C) I = || (3y3 + 6yz + y) dzdy -2-у D) I = II (y - Gyz – y³) dzdy

A) I = Consider the solid bounded by the surfaces S : y = Vr – 1, S2 : y + z = 2, S3 : x = 0, S4 : y= 0, S5 : z = 0 whose graphic representation is (the surface S1 that will be the one of interest is highlighted) y+z = 2 y = V- 1 Consider the vector field F (x, y, z) = (xy, y? + 3z, sin (z)). When calculating I = l. F * nds is obtained: cy²+1 I = (у — 6уг — у) dardy r2 2-y | (y3 + y, y? + 3z, sin(z) · V1+ 4y² dzdy Jo Jo В) I %3 c2 (2-y C) I = || (3y3 + 6yz + y) dzdy -2-у D) I = II (y - Gyz – y³) dzdy

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the solid bounded by the surfaces S : y = Vr – 1, S2 : y + z = 2, S3 : x = 0, S4 : y = 0, S5 : z = 0 whose graphic representation is (the surface S1 that will be the one of interest is highlighted) y+z = 2 y = VI- 1 Consider the vector field F (x, y, z) = (xy, y? + 3z, sin (z)). When calculating I = l. F * nds is obtained: cy²+1 (у — 6уг — у) dardy A) I = r2 r2-y B) I = | (y3 + y, y? + 3z, sin(2)) · V1+ 4y² dzdy Jo Jo c2 r2-y C) I = || (3y3 + 6yz + y) dzdy -2-у D) I = I| (y – Gyz – y³) dzdy -
Transcribed Image Text:Consider the solid bounded by the surfaces S : y = Vr – 1, S2 : y + z = 2, S3 : x = 0, S4 : y = 0, S5 : z = 0 whose graphic representation is (the surface S1 that will be the one of interest is highlighted) y+z = 2 y = VI- 1 Consider the vector field F (x, y, z) = (xy, y? + 3z, sin (z)). When calculating I = l. F * nds is obtained: cy²+1 (у — 6уг — у) dardy A) I = r2 r2-y B) I = | (y3 + y, y? + 3z, sin(2)) · V1+ 4y² dzdy Jo Jo c2 r2-y C) I = || (3y3 + 6yz + y) dzdy -2-у D) I = I| (y – Gyz – y³) dzdy -
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