(a) i – 2r = 3t, r(0) = 1, ±(0) = 5

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Hello I need help for all parts for all the questions. Want to double check my answers. Thank you so much! 

Problem Set 9 (BONUS SET)
(1) Use variation of parameters to find the solution to each IVP
(a) i – 2r = 3t, x(0) = 1, ±(0) = 5
(b) i – 2i – x = 2e-54 – e-7", x(0) = 3, ±(0) = -4
(2) For the differential equation and pairs of numbers A1 and A2 given in each case bellow,
find numbers A and B such that the function
Aedit + Be^at
is a solution to the inhomogeneous equation.
(a) i + å = e2t +e-2", d1 = 2, d2 = -2
(b) ï +x = 3e4 – e*, A1 = 2, 12 = 3
(c) ä +2i + 6x = V5e-t +1, A1 = -1, d2 = 0.
%3D
(3) For the differential equation and frequency w given in each case bellow, find numbers
A and B such that the function
A cos (wt) + B sin(wt)
is a solution to the inhomogeneous equation.
(a) 3ž – i + 2x = 3 cos(2t), w= 2
(b) 5ä + 2i + 7x = sin(3t) + cos(3t), w = 3
(c) # + 2i + 6x = -11 cos(4t) + 3 sin(4t), w= 4.
(4) (BONUS) Show that any combination of trigonometric functions
C1 cos(wt) + C2 sin(wt)
can be expressed as
Rcos (wt + 6)
for R, 6 chosen accordingly in terms of C1 and C2. Then, apply this principle and
find a solution to the second order equation
ü+ 4ủ + 13u = 0,
having the form Re#t cos(wt – 8), for some R, µ, w, and d.
Transcribed Image Text:Problem Set 9 (BONUS SET) (1) Use variation of parameters to find the solution to each IVP (a) i – 2r = 3t, x(0) = 1, ±(0) = 5 (b) i – 2i – x = 2e-54 – e-7", x(0) = 3, ±(0) = -4 (2) For the differential equation and pairs of numbers A1 and A2 given in each case bellow, find numbers A and B such that the function Aedit + Be^at is a solution to the inhomogeneous equation. (a) i + å = e2t +e-2", d1 = 2, d2 = -2 (b) ï +x = 3e4 – e*, A1 = 2, 12 = 3 (c) ä +2i + 6x = V5e-t +1, A1 = -1, d2 = 0. %3D (3) For the differential equation and frequency w given in each case bellow, find numbers A and B such that the function A cos (wt) + B sin(wt) is a solution to the inhomogeneous equation. (a) 3ž – i + 2x = 3 cos(2t), w= 2 (b) 5ä + 2i + 7x = sin(3t) + cos(3t), w = 3 (c) # + 2i + 6x = -11 cos(4t) + 3 sin(4t), w= 4. (4) (BONUS) Show that any combination of trigonometric functions C1 cos(wt) + C2 sin(wt) can be expressed as Rcos (wt + 6) for R, 6 chosen accordingly in terms of C1 and C2. Then, apply this principle and find a solution to the second order equation ü+ 4ủ + 13u = 0, having the form Re#t cos(wt – 8), for some R, µ, w, and d.
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