A hypothetical metal, which is a single crystal and made up of one chemical element, has an FCC crystal structure. Given the density of the metal is 10 g/cm3 and the atomic weight/mass of the metal is 100 g/mol, estimate the atomic radius of the metal. Note: Avogadro's number NA = 6.022×1023 atoms/mol

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### Estimating the Atomic Radius of a Hypothetical Metal

**Problem Statement:**

A hypothetical metal, which is a single crystal and made up of one chemical element, has an FCC (Face-Centered Cubic) crystal structure. Given the density of the metal is 10 g/cm³ and the atomic weight/mass of the metal is 100 g/mol, estimate the atomic radius of the metal.

**Given Data:**
1. Density (\(\rho\)) of the metal: 10 g/cm³
2. Atomic weight/mass (M) of the metal: 100 g/mol
3. Avogadro's number (\(N_A\)): \(6.022 \times 10^{23}\) atoms/mol

**Solution:**

To estimate the atomic radius, we use the following steps:

1. **Determine the Number of Atoms per cm³:**
   The density equation for atoms in a unit volume of the metal can be expressed as:

   \[\rho = \frac{n \cdot M}{V\cdot N_A}\]

   Where \(n\) is the number of atoms per unit cell and \(V\) is the volume of the unit cell. Rearranging for \(V\):

   \[V = \frac{n \cdot M}{\rho \cdot N_A}\]

   For an FCC structure, the number of atoms per unit cell \(n\) is 4.

2. **Calculate the Volume of the Unit Cell:**

   \[V = \frac{4 \cdot 100 \text{ g/mol}}{10 \text{ g/cm}^3 \cdot 6.022 \times 10^{23} \text{ atoms/mol}}\]

3. **Convert the Volume to Appropriate Units:**

   Calculate \(V\) to find the unit cell volume in cm³ and subsequently convert it to cubic angstroms (ų) if necessary for precision in determining the atomic radius.

4. **Determine the Atomic Radius:**
   The volume of a cubic unit cell \(V\) can also be related to the lattice parameter \(a\) (where \(V = a^3\)). For an FCC lattice, the relationship between the lattice parameter \(a\) and the atomic radius \(R\) is:

   \[a = \frac{4R}{\sqrt{2}}\]
Transcribed Image Text:### Estimating the Atomic Radius of a Hypothetical Metal **Problem Statement:** A hypothetical metal, which is a single crystal and made up of one chemical element, has an FCC (Face-Centered Cubic) crystal structure. Given the density of the metal is 10 g/cm³ and the atomic weight/mass of the metal is 100 g/mol, estimate the atomic radius of the metal. **Given Data:** 1. Density (\(\rho\)) of the metal: 10 g/cm³ 2. Atomic weight/mass (M) of the metal: 100 g/mol 3. Avogadro's number (\(N_A\)): \(6.022 \times 10^{23}\) atoms/mol **Solution:** To estimate the atomic radius, we use the following steps: 1. **Determine the Number of Atoms per cm³:** The density equation for atoms in a unit volume of the metal can be expressed as: \[\rho = \frac{n \cdot M}{V\cdot N_A}\] Where \(n\) is the number of atoms per unit cell and \(V\) is the volume of the unit cell. Rearranging for \(V\): \[V = \frac{n \cdot M}{\rho \cdot N_A}\] For an FCC structure, the number of atoms per unit cell \(n\) is 4. 2. **Calculate the Volume of the Unit Cell:** \[V = \frac{4 \cdot 100 \text{ g/mol}}{10 \text{ g/cm}^3 \cdot 6.022 \times 10^{23} \text{ atoms/mol}}\] 3. **Convert the Volume to Appropriate Units:** Calculate \(V\) to find the unit cell volume in cm³ and subsequently convert it to cubic angstroms (ų) if necessary for precision in determining the atomic radius. 4. **Determine the Atomic Radius:** The volume of a cubic unit cell \(V\) can also be related to the lattice parameter \(a\) (where \(V = a^3\)). For an FCC lattice, the relationship between the lattice parameter \(a\) and the atomic radius \(R\) is: \[a = \frac{4R}{\sqrt{2}}\]
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