A hypoeutectoid plain-carbon steel that was slow-cooled from the austenitic region to room temperature contains 9.1 wt% eutectoid ferrite. Assume that no change in structure on cooling from just below the eutectoid temperature to room temperature. Calculate the carbon content of the steel. Temperature ( 1000 900 7+ Fe,C 800 a+7 Eutectoid point 0.022 700 600 500- a+FqC 400 0 0.4 100% Fe 0.77 Pearlite Weight percent carbon Fe,C 6.67 1. Let x = the weight percent carbon of the hypoeutectoid steel (shown as a red line). Now, the relation (ratio) between the eutectoid ferrite to the total ferrite and the proeutectoid ferrite is expressed as: [Eutectoid Ferrite] = [Total Ferrite] - [Proeutectoid Ferrite) ... (eq.1) Fill eq.1 by using x. Express with up to 3 significant digits. (NOTE: Please check the rules for significant figures. For example, 0.012 and 1.23 both have 3 significant digits.) [Eutectoid Ferrite]-[1] [Total Ferrite]-[2] [Proeutectoid Ferrite]-[3] *Check the "Question Hint". Each term in eq. 1 should be expressed as the ratio. W 2. Solve for x Show the carbon content in the steel with up to 3rd decimal place (3 significant digits). A
A hypoeutectoid plain-carbon steel that was slow-cooled from the austenitic region to room temperature contains 9.1 wt% eutectoid ferrite. Assume that no change in structure on cooling from just below the eutectoid temperature to room temperature. Calculate the carbon content of the steel. Temperature ( 1000 900 7+ Fe,C 800 a+7 Eutectoid point 0.022 700 600 500- a+FqC 400 0 0.4 100% Fe 0.77 Pearlite Weight percent carbon Fe,C 6.67 1. Let x = the weight percent carbon of the hypoeutectoid steel (shown as a red line). Now, the relation (ratio) between the eutectoid ferrite to the total ferrite and the proeutectoid ferrite is expressed as: [Eutectoid Ferrite] = [Total Ferrite] - [Proeutectoid Ferrite) ... (eq.1) Fill eq.1 by using x. Express with up to 3 significant digits. (NOTE: Please check the rules for significant figures. For example, 0.012 and 1.23 both have 3 significant digits.) [Eutectoid Ferrite]-[1] [Total Ferrite]-[2] [Proeutectoid Ferrite]-[3] *Check the "Question Hint". Each term in eq. 1 should be expressed as the ratio. W 2. Solve for x Show the carbon content in the steel with up to 3rd decimal place (3 significant digits). A
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A hypoeutectoid plain-carbon steel that was slow-cooled from the austenitic region
to room temperature contains 9.1 wt% eutectoid ferrite.
Assume that no change in structure on cooling from just below the eutectoid
temperature to room temperature. Calculate the carbon content of the steel.
Temperature (
1000
900
7+ Fe,C
800
a+7
Eutectoid point
0.022
700
600
500-
a+FqC
400
0
0.4
100%
Fe
0.77
Pearlite
Weight percent carbon
Fe,C
6.67
1. Let x = the weight percent carbon of the hypoeutectoid steel (shown as a red line).
Now, the relation (ratio) between the eutectoid ferrite to the total ferrite and the
proeutectoid ferrite is expressed as:
[Eutectoid Ferrite] = [Total Ferrite] - [Proeutectoid Ferrite) ... (eq.1)
Fill eq.1 by using x. Express with up to 3 significant digits. (NOTE: Please check the
rules for significant figures. For example, 0.012 and 1.23 both have 3 significant
digits.)
[Eutectoid Ferrite]-[1]
[Total Ferrite]-[2]
[Proeutectoid Ferrite]-[3]
*Check the "Question Hint". Each term in eq. 1 should be expressed as the ratio.
W
2. Solve for x
Show the carbon content in the steel with up to 3rd decimal place (3 significant
digits).
A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F093e7116-3e01-49ad-9157-7a22a5caeb16%2Fea0494a2-d8dd-482b-b386-4d2a831c4f7f%2Fk1asqdj_processed.png&w=3840&q=75)
Transcribed Image Text:A hypoeutectoid plain-carbon steel that was slow-cooled from the austenitic region
to room temperature contains 9.1 wt% eutectoid ferrite.
Assume that no change in structure on cooling from just below the eutectoid
temperature to room temperature. Calculate the carbon content of the steel.
Temperature (
1000
900
7+ Fe,C
800
a+7
Eutectoid point
0.022
700
600
500-
a+FqC
400
0
0.4
100%
Fe
0.77
Pearlite
Weight percent carbon
Fe,C
6.67
1. Let x = the weight percent carbon of the hypoeutectoid steel (shown as a red line).
Now, the relation (ratio) between the eutectoid ferrite to the total ferrite and the
proeutectoid ferrite is expressed as:
[Eutectoid Ferrite] = [Total Ferrite] - [Proeutectoid Ferrite) ... (eq.1)
Fill eq.1 by using x. Express with up to 3 significant digits. (NOTE: Please check the
rules for significant figures. For example, 0.012 and 1.23 both have 3 significant
digits.)
[Eutectoid Ferrite]-[1]
[Total Ferrite]-[2]
[Proeutectoid Ferrite]-[3]
*Check the "Question Hint". Each term in eq. 1 should be expressed as the ratio.
W
2. Solve for x
Show the carbon content in the steel with up to 3rd decimal place (3 significant
digits).
A
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