A hydrogen atom in its ground state is collided with an electron of kinetic energy 13.377 eV. The maximum factor by which the radius of the atom would increase is
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- A hydrogen atom is in its second excited state (n = 3). Using the Bohr theory of the atom, calculate the following. (a) the radius of the orbit nm(b) the linear momentum of the electron kg · m/s(c) the angular momentum of the electron J · s(d) the kinetic energy eV(e) the potential energy eV(f) the total energy eVChapter 39, Problem 044 A hydrogen atom in a state having a binding energy (the energy required to remove an electron) of -1.51 eV makes a transition to a state with an excitation energy (the difference between the energy of the state and that of the ground state) of 10.200 eV. (a) What is the energy of the photon emitted as a result of the transition? What are the (b) higher quantum number and (c) lower quantum number of the transition producing this emission? Use -13.60 eV as the binding energy of an electron in the ground state. (a) Number Units (b) Number Units (c) Number UnitsWhat frequency of light, in THz (Terahertz, or 10^12 Hz), is needed for an electron in a hydrogen atom to go from the n = 2 state to the n = 3 state?
- A hydrogen atom is in its third excited state (n = 4). Using the Bohr theory of the atom, calculate the following. (a) the radius of the orbit nm (b) the linear momentum of the electron kg • m/s (c) the angular momentum of the electron J.S (d) the kinetic energy eV (e) the potential energy eV (f) the total energy eVAn electron in a hydrogen atom is excited from the ground state to the n = 3 state. True or false?a) The wavelength of light emitted when the electron drops from n=3 to n = 1 is longer than that from n = 3 to n = 2.Ggg