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- In a group of 80 students, there are 50 girls and 30 boys such that 65% of the girls graduated from private schools and 15% of the boys graduated from private schools. If a student is randomly selected from this group, find the probability that the selected student graduated from a private school (use the shown tree diagram for your solution). Private School girls Public School Private School boys Public School O 0.800 0.406 O 0.538 O 0.463NoneSuppose we are interested in the pairwise intersection. What is the pairwise intersection for the following events? The set of possible outcomes are s = (1, 2, 3, 4, 5, 6) Suppose E = (1,3, 5); F = (4, 5,6); and G = (2,6) 3. Intersection event of F & G ANSWER
- Make a tree diagram for this question: The probability that a consumer will be exposed to an advertisement for a certain product by seeing a commercial on television is 0.4 The probability that the consumer will be exposed to the product by seeing an advertisement on a billboard is 0.6. The two events, being exposed to the commercial and being exposed to the billboard ad, are assumed to be independent, what is the probability that he or she will be exposed to at least one of the ads?Kylie has 12 pieces of candy left in her Halloween bag. There are 8 pieces of chocolate and 4 pieces of non-chocolate. She chooses a piece of candy at random and then chooses another piece of candy, without replacement. Draw a tree diagram to represent this situation and use it to calculate the probabilities that she picks:Two pieces of chocolate No chocolate At least one piece of non-chocolate One piece of each type2. Two friends, David and Peta, often play squash and tennis with each other. Over the years they have found that David wins 3 out of every 5 rounds of squash and 1 out of every 4 tennis matches. If they play one match of squash and then one tennis match: (a) Draw a tree diagram to describe the situation. (b) Find the probability that David wins both matches. (c) Find the probability that Peta wins the second match.
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- A conditional Probability: P(A | B) is asking what is the probability we get event A if we know that event B occurred. A useful formula: P (A | B) = ||| P(A and B) P(B) Or: P(A | B) = (remaining # of ways to get A) / (remaining number of possible outcomes) A bag has 5 red balls, 7 green balls, and 8 purple balls. Two balls are going to be selected. After the first ball is drawn it is NOT returned to the bag. Find the probability the second is a red ball if you know the first chosen is a red ball. If A = event a red ball is selected: P(A|A) = ?Suppose that events A and B are mutually exclusive with P(A) = 1 2 and P(B) = 1 6 . (Enter your answers as fractions.) (a) Are A and B independent events? Explain how you know. Since the events are mutually exclusive we know P(A|B) = which P(A) and thus the events are . (b) Are A and B complementary events? Explain how you know. We know that P(A) + P(B) = . And, since P(A) + P(B) 1, the events A and B complementary events.Philippus flips a fair coin 100 times. Let the outcome be the number of heads that he sees. Philippus now flip his fair coin n times. He is interested in the event "there are (strictly) more heads than tails." What's the probability of this event for the following values of n? (g) an arbitrary positive integer n