A household refrigerator that has a power input of 450 W and a COP of 1.55 is to cool five large watermelons, 10 kg each, to 8°C. If the watermelons are initially at 28°C, determine how long it will take for the refrigerator to cool them. The watermelons can be treated as water whose specific heat is 4.2 kJ/kg-"C. Is your answer realistic or optimistic? The time taken for the refrigerator to cool the watermelons is [6222.22] min and the answer is optimistic

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A household refrigerator that has a power input of 450 W and a COP of 1.55 is to cool five large watermelons, 10 kg each, to 8°C. If
the watermelons are initially at 28°C, determine how long it will take for the refrigerator to cool them. The watermelons can be
treated as water whose specific heat is 4.2 kJ/kg-°C. Is your answer realistic or optimistic?
The time taken for the refrigerator to cool the watermelons is [6222.22] min and the answer is optimistic
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Transcribed Image Text:A household refrigerator that has a power input of 450 W and a COP of 1.55 is to cool five large watermelons, 10 kg each, to 8°C. If the watermelons are initially at 28°C, determine how long it will take for the refrigerator to cool them. The watermelons can be treated as water whose specific heat is 4.2 kJ/kg-°C. Is your answer realistic or optimistic? The time taken for the refrigerator to cool the watermelons is [6222.22] min and the answer is optimistic Drev 3 of 9 # Next Next >
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