A house was valued at $115,000 in the year 1987. The value appreciated to $145,000 by the year 2006. Use the compound interest formula S = P(1 + r)' to answer the following questions. A) What was the annual growth rate between 1987 and 2006? Round the growth rate to 4 decimal places. B) What is the correct answer to part A written in percentage form? r = %. C) Assume that the house value continues to grow by the same percentage. What will the value equal in the year 2009 ? value = S Round to the negrest thoucand dollers

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A house was valued at $115,000 in the year 1987. The value appreciated to $145,000 by the
2006.
year
Use the compound interest formula S = P(1 + r)' to answer the following questions.
A) What was the annual growth rate between 1987 and 2006?
r =
Round the growth rate to 4 decimal places.
B) What is the correct answer to partA written in percentage form?
r =
%.
C) Assume that the house value continues to grow by the same percentage. What will the value
equal in the year 2009 ?
value =
2$
Round to the nearest thousand dollars.
Transcribed Image Text:A house was valued at $115,000 in the year 1987. The value appreciated to $145,000 by the 2006. year Use the compound interest formula S = P(1 + r)' to answer the following questions. A) What was the annual growth rate between 1987 and 2006? r = Round the growth rate to 4 decimal places. B) What is the correct answer to partA written in percentage form? r = %. C) Assume that the house value continues to grow by the same percentage. What will the value equal in the year 2009 ? value = 2$ Round to the nearest thousand dollars.
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