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A hot-rolled steel has a yield strength of Sy Syc = 100 kpsi and a true strain at fracture of ɛf = 0.55. Estimate the factor of safety for the following principal stress states: (a) ox = 70 kpsi, ơy = 70 kpsi, txy = 0 kpsi 40 kpsi, txy = –15 kpsi 45 kpsi -60 kpsi, try 30 kpsi (b)ox = 60 kpsi, ơy C)ox = 0 kpsi, ơy = 40 kpsi, try = -40 kpsi, ơy 15 kpsi (d) 0x (e) 01 = 30 kpsi, o2 = 30 kpsi, 03

A hot-rolled steel has a yield strength of Sy Syc = 100 kpsi and a true strain at fracture of ɛf = 0.55. Estimate the factor of safety for the following principal stress states: (a) ox = 70 kpsi, ơy = 70 kpsi, txy = 0 kpsi 40 kpsi, txy = –15 kpsi 45 kpsi -60 kpsi, try 30 kpsi (b)ox = 60 kpsi, ơy C)ox = 0 kpsi, ơy = 40 kpsi, try = -40 kpsi, ơy 15 kpsi (d) 0x (e) 01 = 30 kpsi, o2 = 30 kpsi, 03

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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A hot-rolled steel has a yield strength of Syf = Syc = 100 kpsi and a true strain at fracture of ɛf = 0.55. Estimate the factor of safety for the following principal stress states: : 70 kpsi, txy = 0 kpsi 40 kpsi, txy = –15 kpsi 45 kpsi (a) ox = 70 kpsi, ơy (b)ox = 60 kpsi, ơy 0 kpsi, ơy = -40 kpsi, oy = -60 kpsi, Txy 40 kpsi, txy (c)0x = (d) 0x (e) 01 = 30 kpsi, o2 %3| 15 kpsi 30 kpsi 30 kpsi, 03
Transcribed Image Text:A hot-rolled steel has a yield strength of Syf = Syc = 100 kpsi and a true strain at fracture of ɛf = 0.55. Estimate the factor of safety for the following principal stress states: : 70 kpsi, txy = 0 kpsi 40 kpsi, txy = –15 kpsi 45 kpsi (a) ox = 70 kpsi, ơy (b)ox = 60 kpsi, ơy 0 kpsi, ơy = -40 kpsi, oy = -60 kpsi, Txy 40 kpsi, txy (c)0x = (d) 0x (e) 01 = 30 kpsi, o2 %3| 15 kpsi 30 kpsi 30 kpsi, 03
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