A hot cylinder ingot of 50mm diameter and 200mm long is taken out from the fuatace at 800°C and dipped in water till its temperature fall to 500°C. Then, it is dırectly exposed to air till its temperature falls to 100°C. Find the total time required for the ingot to reach the temperature from 800°C to 100°C. Take the following k(thermal conductivity of ingot) = 60w/m°C: c(specific heat of ingot) = 200J/m°C; p(density of ingot material) = 800kg/m:
A hot cylinder ingot of 50mm diameter and 200mm long is taken out from the fuatace at 800°C and dipped in water till its temperature fall to 500°C. Then, it is dırectly exposed to air till its temperature falls to 100°C. Find the total time required for the ingot to reach the temperature from 800°C to 100°C. Take the following k(thermal conductivity of ingot) = 60w/m°C: c(specific heat of ingot) = 200J/m°C; p(density of ingot material) = 800kg/m:
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:4.
A hot cylinder ingot of 50mm diameter and 200mm long is taken out from the
fuatace at 800°C and dipped in water till its temperature fall to 500°C. Then, it is
dırectly exposed to air till its temperature falls to 100°C. Find the total time required
for the ingot to reach the temperature from 800°C to 100°C. Take the following:
k(thermal conductivity of ingot) = 60w/m°C:
c(specific heat of ingot) = 200j/m°C;
p(density of ingot material) = 800kg/m:
h,(heat transfer coefficient in water) = 200w/m2"C:
ha(heat transfer coefficient in air) = 20w/m2"C;
Temperature of air or water = 30°C
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