A hospital would like to determine the mean length of stay for its patients having abdominal surgery. A sample of 16 patients revealed a sample mean of 6.8 days and a sample standard deviation of 1.6 days. Assume that the lengths of stay are approximately normally distributed. Find a 95% confidence interval for the mean length of stay for patients with abdominal surgery. Round the endpoints to two decimal places, if necessary

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
icon
Related questions
Question
A hospital would like to determine the mean length of stay for its patients having abdominal surgery. A sample of 16 patients revealed a sample mean of 6.8 days and a
sample standard deviation of 1.6 days. Assume that the lengths of stay are approximately normally distributed. Find a 95 % confidence interval for the mean length of
stay for patients with abdominal surgery. Round the endpoints to two decimal places, if necessary.
ren
Transcribed Image Text:A hospital would like to determine the mean length of stay for its patients having abdominal surgery. A sample of 16 patients revealed a sample mean of 6.8 days and a sample standard deviation of 1.6 days. Assume that the lengths of stay are approximately normally distributed. Find a 95 % confidence interval for the mean length of stay for patients with abdominal surgery. Round the endpoints to two decimal places, if necessary. ren
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 12 images

Blurred answer
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt