A hospital researcher is interested in the number of times the average post-op patient will ring the nurse during a 12-hour shift. For a random sample of 50 patients, the following information was obtained. Let X = the number of times a patient rings the nurse during a 12-hour shift. For this exercise, x = 0, 1, 2, 3, 4, 5. P(x) = the probability that X takes on value x. Why is this a discrete probability distribution function (two reasons)? The image contains a probability table related to a discrete random variable $X$ with possible values ranging from 0 to 5. The table lists the probability mass function $P(x)$ which defines the probability that $X$ equals a particular value. Here are the details of the table:| $X$ | $P(x)$ ||-------|---------------|| 0 | $P(x = 0) = \frac{4}{50}$ || 1 | $P(x = 1) = \frac{8}{50}$ || 2 | $P(x = 2) = \frac{16}{50}$|| 3 | $P(x = 3) = \frac{14}{50}$|| 4 | $P(x = 4) = \frac{6}{50}$ || 5 | $P(x = 5) = \frac{2}{50}$ |Each entry shows the value of $X$ and the corresponding probability of that value occurring. This is a typical way to represent a discrete probability distribution, aiding in statistical analysis and probability calculations.

Name: A hospital researcher is interested in the number of times the average
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Description: A hospital researcher is interested in the number of times the average post-op patient will ring the nurse during a 12-hour shift. For a random sample of 50 patients, the following information was obtained. Let X = the number of times a patient rings

Consider a random variable x with probability distribution of p(x). Now, p(x) is said to be a valid…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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A hospital researcher is interested in the number of times the average post-op patient will ring the nurse during a 12-hour shift. For a random sample of 50 patients, the following information was obtained. Let X = the number of times a patient rings the nurse during a 12-hour shift. For this exercise, x = 0, 1, 2, 3, 4, 5. P(x) = the probability that X takes on value x. Why is this a discrete probability distribution function (two reasons)?

The image contains a probability table related to a discrete random variable $X$ with possible values ranging from 0 to 5. The table lists the probability mass function $P(x)$ which defines the probability that $X$ equals a particular value. Here are the details of the table:

| $X$ | $P(x)$ |
|-------|---------------|
| 0 | $P(x = 0) = \frac{4}{50}$ |
| 1 | $P(x = 1) = \frac{8}{50}$ |
| 2 | $P(x = 2) = \frac{16}{50}$|
| 3 | $P(x = 3) = \frac{14}{50}$|
| 4 | $P(x = 4) = \frac{6}{50}$ |
| 5 | $P(x = 5) = \frac{2}{50}$ |

Each entry shows the value of $X$ and the corresponding probability of that value occurring. This is a typical way to represent a discrete probability distribution, aiding in statistical analysis and probability calculations.

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