A horse is pulling a sled with 20O N of horizontal force against an average of 100 N of friction for 300 m of distance. How many Joules of net work is done to the sled?

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problem Explanation**

**Problem Statement:**
A horse is pulling a sled with 200 N of horizontal force against an average of 100 N of friction for 300 meters of distance. How many Joules of net work is done to the sled?

**Solution:**

1. **Calculate the total work done by the horse:**
   - Work is calculated by the formula: \( W = F \times d \)
   - **Force applied by the horse (F)**: 200 N
   - **Distance (d)**: 300 m
   - **Work done by the horse (W)**: 
     \[
     W = 200 \, \text{N} \times 300 \, \text{m} = 60000 \, \text{J}
     \]

2. **Calculate the work done against friction:**
   - **Frictional force (F_f)**: 100 N
   - **Distance (d)**: 300 m
   - **Work done against friction (W_f)**: 
     \[
     W_f = 100 \, \text{N} \times 300 \, \text{m} = 30000 \, \text{J}
     \]

3. **Calculate the net work done on the sled:**
   - **Net Work (W_net)** = Work done by horse - Work done against friction
   - \[
     W_{net} = 60000 \, \text{J} - 30000 \, \text{J} = 30000 \, \text{J}
     \]

**Answer:**
The net work done to the sled is 30000 Joules.
Transcribed Image Text:**Physics Problem Explanation** **Problem Statement:** A horse is pulling a sled with 200 N of horizontal force against an average of 100 N of friction for 300 meters of distance. How many Joules of net work is done to the sled? **Solution:** 1. **Calculate the total work done by the horse:** - Work is calculated by the formula: \( W = F \times d \) - **Force applied by the horse (F)**: 200 N - **Distance (d)**: 300 m - **Work done by the horse (W)**: \[ W = 200 \, \text{N} \times 300 \, \text{m} = 60000 \, \text{J} \] 2. **Calculate the work done against friction:** - **Frictional force (F_f)**: 100 N - **Distance (d)**: 300 m - **Work done against friction (W_f)**: \[ W_f = 100 \, \text{N} \times 300 \, \text{m} = 30000 \, \text{J} \] 3. **Calculate the net work done on the sled:** - **Net Work (W_net)** = Work done by horse - Work done against friction - \[ W_{net} = 60000 \, \text{J} - 30000 \, \text{J} = 30000 \, \text{J} \] **Answer:** The net work done to the sled is 30000 Joules.
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