A horse is pulling a sled with 20O N of horizontal force against an average of 100 N of friction for 300 m of distance. How many Joules of net work is done to the sled?
A horse is pulling a sled with 20O N of horizontal force against an average of 100 N of friction for 300 m of distance. How many Joules of net work is done to the sled?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Problem Explanation**
**Problem Statement:**
A horse is pulling a sled with 200 N of horizontal force against an average of 100 N of friction for 300 meters of distance. How many Joules of net work is done to the sled?
**Solution:**
1. **Calculate the total work done by the horse:**
- Work is calculated by the formula: \( W = F \times d \)
- **Force applied by the horse (F)**: 200 N
- **Distance (d)**: 300 m
- **Work done by the horse (W)**:
\[
W = 200 \, \text{N} \times 300 \, \text{m} = 60000 \, \text{J}
\]
2. **Calculate the work done against friction:**
- **Frictional force (F_f)**: 100 N
- **Distance (d)**: 300 m
- **Work done against friction (W_f)**:
\[
W_f = 100 \, \text{N} \times 300 \, \text{m} = 30000 \, \text{J}
\]
3. **Calculate the net work done on the sled:**
- **Net Work (W_net)** = Work done by horse - Work done against friction
- \[
W_{net} = 60000 \, \text{J} - 30000 \, \text{J} = 30000 \, \text{J}
\]
**Answer:**
The net work done to the sled is 30000 Joules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0f85ff8-2ea0-4d43-a0c0-84de96cc63b8%2F5b7933f0-6409-484c-952d-a3eb8c7a5b0e%2F411wytl_processed.png&w=3840&q=75)
Transcribed Image Text:**Physics Problem Explanation**
**Problem Statement:**
A horse is pulling a sled with 200 N of horizontal force against an average of 100 N of friction for 300 meters of distance. How many Joules of net work is done to the sled?
**Solution:**
1. **Calculate the total work done by the horse:**
- Work is calculated by the formula: \( W = F \times d \)
- **Force applied by the horse (F)**: 200 N
- **Distance (d)**: 300 m
- **Work done by the horse (W)**:
\[
W = 200 \, \text{N} \times 300 \, \text{m} = 60000 \, \text{J}
\]
2. **Calculate the work done against friction:**
- **Frictional force (F_f)**: 100 N
- **Distance (d)**: 300 m
- **Work done against friction (W_f)**:
\[
W_f = 100 \, \text{N} \times 300 \, \text{m} = 30000 \, \text{J}
\]
3. **Calculate the net work done on the sled:**
- **Net Work (W_net)** = Work done by horse - Work done against friction
- \[
W_{net} = 60000 \, \text{J} - 30000 \, \text{J} = 30000 \, \text{J}
\]
**Answer:**
The net work done to the sled is 30000 Joules.
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