### Educational Example: Magnetic Force on a Power Line**Problem Statement:**A horizontal power line carries a current of 4800 A from south to north. Earth's magnetic field (62.6 µT) is directed toward the north and is inclined downward at 62.0° to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 110 m of the line due to Earth's field.**Questions:**(a) - **Number**: [Input Box]- **Units**: [Dropdown Box](b) - [Dropdown Box]**Explanation of Input Fields:**- **(a) Number**: Enter the magnitude of the magnetic force in the input box provided.- **Units**: Choose the appropriate units for the magnetic force from the dropdown menu.- **(b)** Direction of the magnetic force: Select the direction from the dropdown menu as per the magnetic force calculated.The solution involves applying the formula for the magnetic force on a current-carrying conductor in a magnetic field:\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]where:- \( I \) is the current (4800 A),- \( L \) is the length of the conductor (110 m),- \( B \) is the magnetic field strength (62.6 µT or \( 62.6 \times 10^{-6} \) T),- \( \theta \) is the angle between the direction of the current and the magnetic field (62.0°).The direction of the force will be determined using the right-hand rule for magnetic forces.

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A horizontal power line carries a current of 4800 A from south to north. Earth's magnetic field (62.6 µT) is directed toward the north and is inclined downward at 62.0° to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 110 m of the line due to Earth's field. (a) Number i (b) Units

A horizontal power line carries a current of 4800 A from south to north. Earth's magnetic field (62.6 µT) is directed toward the north and is inclined downward at 62.0° to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 110 m of the line due to Earth's field. (a) Number i (b) Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

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### Educational Example: Magnetic Force on a Power Line

**Problem Statement:**
A horizontal power line carries a current of 4800 A from south to north. Earth's magnetic field (62.6 µT) is directed toward the north and is inclined downward at 62.0° to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 110 m of the line due to Earth's field.

**Questions:**
(a)
- **Number**: [Input Box]
- **Units**: [Dropdown Box]

(b)
- [Dropdown Box]

**Explanation of Input Fields:**
- **(a) Number**: Enter the magnitude of the magnetic force in the input box provided.
- **Units**: Choose the appropriate units for the magnetic force from the dropdown menu.
- **(b)** Direction of the magnetic force: Select the direction from the dropdown menu as per the magnetic force calculated.

The solution involves applying the formula for the magnetic force on a current-carrying conductor in a magnetic field:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]
where:
- \( I \) is the current (4800 A),
- \( L \) is the length of the conductor (110 m),
- \( B \) is the magnetic field strength (62.6 µT or \( 62.6 \times 10^{-6} \) T),
- \( \theta \) is the angle between the direction of the current and the magnetic field (62.0°).

The direction of the force will be determined using the right-hand rule for magnetic forces.

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