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A horizontal, frictionless channel of circular cross-section and diameter equal to 5 feet flows at a depth of 3 feet and a velocity of 2 ft/s. a. Find the discharge in the channel. b. Determine the specific energy of this flow. c. Determine the Froude number of this flow.

A horizontal, frictionless channel of circular cross-section and diameter equal to 5 feet flows at a depth of 3 feet and a velocity of 2 ft/s. a. Find the discharge in the channel. b. Determine the specific energy of this flow. c. Determine the Froude number of this flow.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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A horizontal, frictionless channel of circular cross-section and diameter equal to 5 feet flows at a depth of 3 feet and a velocity of 2 ft/s. a. Find the discharge in the channel. b. Determine the specific energy of this flow. c. Determine the Froude number of this flow. d. What is the maximum upward step height (AZmax) that this flow can tolerate without a choke? Assume yc ≤r. Set up the equation to solve for yc, which will be "expensive" so solve. Move forward with the problem knowing that computationally 1.126 ft. Yc =
Transcribed Image Text:A horizontal, frictionless channel of circular cross-section and diameter equal to 5 feet flows at a depth of 3 feet and a velocity of 2 ft/s. a. Find the discharge in the channel. b. Determine the specific energy of this flow. c. Determine the Froude number of this flow. d. What is the maximum upward step height (AZmax) that this flow can tolerate without a choke? Assume yc ≤r. Set up the equation to solve for yc, which will be "expensive" so solve. Move forward with the problem knowing that computationally 1.126 ft. Yc =
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Note:- The given question is having multiple sub parts, as per the policy of Bartleby we are providing solution only to first three sub parts.

Given:-

Channel is having circular cross section

Diameter of channel = 5 feet

Depth of flow = 3 feet

Velocity = 2 ft/s

To find:-

Discharge

Specific energy

Froude number

Concept:-

Discharge of flow is given as

Q=AVWhereQ=DischargeA=Wetted area of flowV=Velocity of flow

Specific energy of flow is given as

E=y+V22gWhereE=Specific energyy=Depth of flowV=Velocity of flowg=Acceleration due to gravity=32.2 ft/s2

Froude number of flow is given as

Fr=VghWhereFr=Froude numberV=Velocity of flowg=Acceleration due to gravityh=Hydraulic depth

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