A horizontal force of 8.0-newtons is used to pull a 20.-newton wooden box moving toward the right actoss a horizontal wood surface, as shown. F = 8.0 N 20. N wooden box Wood Calculate the magnitude of the friction force acting on the box. Show all work, including the equation and substitution with units B i U AA E E x T- E A:

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### Example Problem: Calculating Friction Force

#### Problem Statement:
A horizontal force of 8 newtons is used to pull a 20-newton wooden box moving toward the right across a horizontal wood surface, as shown.

**Diagram Description:**
- The diagram shows a wooden box on a wood surface.
- The rectangular wooden box is labeled as "20 N wooden box."
- An arrow to the right of the box indicates a force \( F \) of 8.0 N being applied horizontally.

#### Task:
Calculate the magnitude of the friction force acting on the box. Show all work, including the equation and substitution with units.

**Solution:**
To calculate the friction force, use the following steps:

1. **Identify the normal force (\( F_N \)):**
   Since the box is on a horizontal surface, the normal force is equal to the weight of the box.
   \[
   F_N = 20 \text{ N}
   \]

2. **Use the formula for friction force (\( F_{friction} \)):**
   The friction force (\( F_f \)) is given by:
   \[
   F_f = \mu \times F_N
   \]
   where \( \mu \) is the coefficient of friction. For this particular problem, we do not have the coefficient of friction given, but under typical conditions for wood on wood, this value generally ranges around 0.5. 

3. **Determine the value of the coefficient of friction for the system:**
   Since the body is moving, it implies that the applied force and frictional force are balanced.

\[
F_{applied} = F_{friction}
\]

\[
\text{Therefore}\quad 8 \text{ N} = \mu \times 20 \text{ N}
\]

\[
\mu = \frac{8 \text{ N}}{20 \text{ N}} 
\]

\[
\mu = 0.4
\]

Thus, the magnitude of the friction force acting on the box is 8.0 N which matches the applied force, indicating that it is the force necessary to keep the box moving at a constant velocity across the surface.
Transcribed Image Text:### Example Problem: Calculating Friction Force #### Problem Statement: A horizontal force of 8 newtons is used to pull a 20-newton wooden box moving toward the right across a horizontal wood surface, as shown. **Diagram Description:** - The diagram shows a wooden box on a wood surface. - The rectangular wooden box is labeled as "20 N wooden box." - An arrow to the right of the box indicates a force \( F \) of 8.0 N being applied horizontally. #### Task: Calculate the magnitude of the friction force acting on the box. Show all work, including the equation and substitution with units. **Solution:** To calculate the friction force, use the following steps: 1. **Identify the normal force (\( F_N \)):** Since the box is on a horizontal surface, the normal force is equal to the weight of the box. \[ F_N = 20 \text{ N} \] 2. **Use the formula for friction force (\( F_{friction} \)):** The friction force (\( F_f \)) is given by: \[ F_f = \mu \times F_N \] where \( \mu \) is the coefficient of friction. For this particular problem, we do not have the coefficient of friction given, but under typical conditions for wood on wood, this value generally ranges around 0.5. 3. **Determine the value of the coefficient of friction for the system:** Since the body is moving, it implies that the applied force and frictional force are balanced. \[ F_{applied} = F_{friction} \] \[ \text{Therefore}\quad 8 \text{ N} = \mu \times 20 \text{ N} \] \[ \mu = \frac{8 \text{ N}}{20 \text{ N}} \] \[ \mu = 0.4 \] Thus, the magnitude of the friction force acting on the box is 8.0 N which matches the applied force, indicating that it is the force necessary to keep the box moving at a constant velocity across the surface.
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