A horizontal cantilever beam, made of steel, is pin-jointed with a vertical brass rod at the end B, as shown in Figure 3. The end C of the rod is pin- jointed to the upper wall. A uniformly distributed load w and a point load P are applied on the beam and rod, as shown. The second moment of area of the beam / = 2 x 106 mm4 and the Young's modulus of steel Esteel = 210 GPa. The brass rod has diameter 5 mm and the Young's modulus of brass Eprass = 110 GPa. Under the current loads, the brass rod is extended by 2 mm. 600 mm B 800 mm P = 2 kN Figure 3

Structural Analysis
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Chapter2: Loads On Structures
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A horizontal cantilever beam, made of steel, is pin-jointed with a vertical brass rod at the end B, as shown in Figure 3. The end C of the rod is pin-
jointed to the upper wall. A uniformly distributed load w and a point load P are applied on the beam and rod, as shown. The second moment of area of
the beam / = 2 x 106 mm4 and the Young's modulus of steel Esteel = 210 GPa. The brass rod has diameter 5 mm and the Young's modulus of brass Eprass
= 110 GPa. Under the current loads, the brass rod is extended by 2 mm.
600 mm
1 A
800 mm
P= 2 kN
Figure 3
Transcribed Image Text:A horizontal cantilever beam, made of steel, is pin-jointed with a vertical brass rod at the end B, as shown in Figure 3. The end C of the rod is pin- jointed to the upper wall. A uniformly distributed load w and a point load P are applied on the beam and rod, as shown. The second moment of area of the beam / = 2 x 106 mm4 and the Young's modulus of steel Esteel = 210 GPa. The brass rod has diameter 5 mm and the Young's modulus of brass Eprass = 110 GPa. Under the current loads, the brass rod is extended by 2 mm. 600 mm 1 A 800 mm P= 2 kN Figure 3
34. Determine the axial tensile force F, in the brass rod:
OA. F, = 3188.45 N
OB. F, = 4592.32 N
OC. F, = 6429.97 N
OD. F, = 7295.83 N
35. When superposition method is applied to solve this beam deflection problem, determine the deflection of the beam at the end B caused by the tensile force F, only:
OA. – 1.258 mm
OB. – 2.965 mm
OC. - 3.774 mm
OD. – 4.832 mm
36. When superposition method is applied to solve this beam deflection problem, determine the deflection of the beam at the end B caused by the load P only:
OA. – 0.339 mm
OB. – 0.572 mm
OC. - 0.813 mm
OD. - 1.635 mm
37. Determine the magnitude of the load w:
OA. w = 24.51 N/mm
OB. w = 28.77 N/mm
OC. w = 38.93 N/mm
OD. w = 47.36 N/mm
Transcribed Image Text:34. Determine the axial tensile force F, in the brass rod: OA. F, = 3188.45 N OB. F, = 4592.32 N OC. F, = 6429.97 N OD. F, = 7295.83 N 35. When superposition method is applied to solve this beam deflection problem, determine the deflection of the beam at the end B caused by the tensile force F, only: OA. – 1.258 mm OB. – 2.965 mm OC. - 3.774 mm OD. – 4.832 mm 36. When superposition method is applied to solve this beam deflection problem, determine the deflection of the beam at the end B caused by the load P only: OA. – 0.339 mm OB. – 0.572 mm OC. - 0.813 mm OD. - 1.635 mm 37. Determine the magnitude of the load w: OA. w = 24.51 N/mm OB. w = 28.77 N/mm OC. w = 38.93 N/mm OD. w = 47.36 N/mm
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